Primero Uno, Number One

From the proportion mass table,

$\begin{matrix} \begin{matrix} m_p & 0 \\ 2m_p & 2^{n-2} \\ 4m_p & 2^{n-4}\\8m_p &2^{n-6} \\..&..\end{matrix} &  \\  &  \end{matrix}$
we see that the general particle,  $m_{p\,i}$

$\begin{matrix} 2^{i}m_p &2^{n-2i}  \end{matrix}$

when

$i=\cfrac{n}{2}$

we have

$m_{p\,n/2}=(\sqrt{2})^nm_p$

The single heaviest particle in the universe!  The top dog,  The Primero Onu, Number One.