But for comparison sake, and other good wine,
we will kept the second version in mind. Maybe,
In this case earth is a g− particle in the new sign assignment.
Whether a particle exert an attractive or repulsive force depends on the boundary conditions applied to F, the force density that results from a change in ψ, ∂ψ∂x around the particle. A negative F implies ψ extends further from the center and the mass of the particle is smaller.
What to do?
Find the particle pairs, find the smaller mass in the pair, spins/rotates, collide and sent it down a coil conductor and determine the type(s) of field/energy that manifests. The less massive particle has a negative F and is assigned as a negative particle.
