But for comparison sake, and other good wine,
we will kept the second version in mind. Maybe,
In this case earth is a \(g^{-}\) particle in the new sign assignment.
Whether a particle exert an attractive or repulsive force depends on the boundary conditions applied to \(F\), the force density that results from a change in \(\psi\), \(\cfrac{\partial\psi}{\partial\,x}\) around the particle. A negative \(F\) implies \(\psi\) extends further from the center and the mass of the particle is smaller.
What to do?
Find the particle pairs, find the smaller mass in the pair, spins/rotates, collide and sent it down a coil conductor and determine the type(s) of field/energy that manifests. The less massive particle has a negative \(F\) and is assigned as a negative particle.
