Both negative and positive gravity particles exist in the \(t_g\) time dimension and interact as gravity particles.
A negative gravity particle does not interact with a proton, simply because they exist in different realms.
But they are all here!?
Because of this non-interaction, we conclude that the forces are orthogonal and \(t_c\) is orthogonal to \(t_g\). This give raise to the graphical representation of particle as the vertex of a cube.
\(F\) and \(\psi\) was derived independent of such a representation.
When the time dimensions are aligned, \(F\) is also rotated. The direction of the space dimension gives the direction of positive \(F\). We find that a negative particle exert a force that is opposite to a positive particle. There is no need to make \(F\) negative again.
Why is the mass of an electron smaller than a proton? It might not be, that all negative particles have smaller mass compared to their positive counterpart.
They are still all here.
When the time dimensions are aligned, \(F\) is also rotated. The direction of the space dimension gives the direction of positive \(F\). \(F\) pointing in the opposite direction indicates a negative \(F\). For \(F\) to be negative, \(\psi\) extends further into space resulting in a smaller particle mass. For a negative particle, we define it to be exerting a negative force. All negative particles will then have smaller particle mass compared to the corresponding positive particle.
The latter reasoning can be refuted by showing that not all negative particles have relatively smaller mass. However, all negative particles having relatively smaller mass compared to their positive counterpart does not prove that the latter reasoning is right.
\(F\) has two constants of integration that are adjusted for boundary conditions. If \(F(0)\lt 0\) then \(F\) shifts to the right resulting in greater \(\psi\) and so less particle mass. A rotated \(F\) as the time dimensions align provides the boundary condition that \(F(0)\lt 0\).
???!
When the time dimensions are aligned, \(F\) is also rotated. The direction of the space dimension gives the direction of positive \(F\). \(F\) pointing in the opposite direction indicates a negative \(F\). For \(F\) to be negative, \(\psi\) extends further into space resulting in a smaller particle mass. For a negative particle, we define it to be exerting a negative force. All negative particles will then have smaller particle mass compared to the corresponding positive particle.
The latter reasoning can be refuted by showing that not all negative particles have relatively smaller mass. However, all negative particles having relatively smaller mass compared to their positive counterpart does not prove that the latter reasoning is right.
\(F\) has two constants of integration that are adjusted for boundary conditions. If \(F(0)\lt 0\) then \(F\) shifts to the right resulting in greater \(\psi\) and so less particle mass. A rotated \(F\) as the time dimensions align provides the boundary condition that \(F(0)\lt 0\).
???!
