If,
\(q=m.4\pi a_{\psi}^{ 2 }\)
from the post "Pound To Rescue Permittivity" dated 30 May 2016, also,
\(\cfrac{q}{\varepsilon_o}=4\pi a^2_{\psi}m.2c^2ln(cosh(\pi))\)
\(\varepsilon_o\) resists the spread of \(q\) into the region with permittivity, \(\varepsilon_o\).
If each charge is a portal to a storage of flux, \(\varepsilon_o\) resist or aid (\(\varepsilon_o\lt 1\)) the flow of flux from the storage.
\(\cfrac{q}{\varepsilon_o}=q.2c^2ln(cosh(\pi))\)
\(\cfrac{1}{\varepsilon_o.2ln(cosh(\pi))}=c^2\)
And we start a treasure hunt!
Note: This posts has lost its original meaning. What was it about? \(ln(cosh(\pi))\) is arbitrary. For a basic particle this could be,
\(ln(cosh(\cfrac { G }{ \sqrt { 2{ mc^{ 2 } } } }a_{\psi\,c}))=\cfrac{1}{4}\)
\(ln(cosh(0.7369))=\cfrac{1}{4}\)
