Gravitational Constant At Last!

From the post "Pound To Rescue Permittivity" dated 30 May 2016,

$q=m.4\pi a^2_{\psi}= \cfrac { dq }{dr}|_{ r=a_{\psi} }$

This points to surface property, that the behavior of $q$, $\frac { dq }{ dr }$ at the surface boundary $r=a_{\psi}$ determines the field extended by the particle.  But it leads to high values for gravity and the gravitational constant, when the particles are large gravity particles (because there was a mistake).

If we reformulate more clearly,

$M=m.4\pi a^2_{\psi}= \cfrac { dM }{dr}|_{ r=a_{\psi} }$

Because,

$F_{ { G } }\cfrac { 1 }{ 4\pi a^{ 2 }_{ \psi  } } =G\cfrac { M }{ a^{ 2 }_{ \psi  } } =2{ mc^{ 2 } }.ln(cosh(\pi ))$

We note that $GM$ takes the place of $\cfrac{q}{4\pi\varepsilon_o}$.  We have

$G\cfrac { M }{ a^{ 2 }_{ \psi  } } =2{ mc^{ 2 } }.ln(cosh(\pi ))$

$G\cfrac { m.4\pi a^2_{\psi}}{ a^{ 2 }_{ \psi  } } =2{ mc^{ 2 } }.ln(cosh(\pi ))$

$G=\cfrac { c^{ 2 }ln(cosh(\pi )) }{ 2\pi  }$

$G=\cfrac{299792458^2*ln(cosh(\pi))}{2\pi}$

$G=3.504958e16$

To account for entanglement, we divide by the Durian constant.

$G=\cfrac{299792458^2*ln(cosh(\pi))}{2\pi*9.029022e26 }$

$G=3.88188e-11$

which is just a coincident.

Compare this with the quoted value of $G=6.67259e(-11)$, we missed by a factor of $\sqrt{3}$.

$G*\sqrt{3}=6.7236e-11$

What happened?  It could be,

where one dimensional space along $r$ is elevated to three dimensional space.  A particle in one dimension is now a body with extends in two other dimensions.  The body "feels" the force in these additional two dimensions and the result is a factor of $\sqrt{3}$ ( used to be called Boltzmann).

Good night.