\(\psi\) is energy oscillating between two dimensions. At the center of the particle, \(\psi\) departs from space returns to the time dimension (\(v_x=c\) and \(v_t=0\)). On the surface of the particle where \(iv_x=v_{x\bot}=c\) and \(iv_t=v_{t\bot}=0\), \(\psi\) returns to the space dimension. This space dimension is orthogonal to that at the center of the particle. Space at the center and the surface of the particle are connected through \(v_{t}=0\), but twisted. \(\psi\) emerge through an orthogonal dimension in space at the surface, as if it has been Fourier transformed at the center of the particle.
\(\psi\) recycles itself. \(\psi\) need not return to the same particle.
And so, \(\psi\) is not delimited to \(a_{\psi}\) but extends to infinity.
The correct graph of \(\psi\) should be,
This does not mean \(\psi\), energy density is unbounded, \(\psi\) is instead bounded by \(v_{x\bot}=c\) where it "drops" into an orthogonal time dimension.
Whether \(\psi\) "drops" at the edge from the space dimension and appear at the center in the time dimension or \(\psi\) "disappear" at the center from the space dimension and "emerges" at the edge in the time dimension, are equivalent orthogonal view of the same situation.
\(\psi\) is oscillating between two dimensions, when it is maximum in one dimension it is minimum in the other dimension.
If \(\psi\) is subjected to \(F_{\rho}\), \(\psi\) is also subjected to the \(\psi\) vs \(x\) graph above. As \(\psi\) approaches the universe center, \(\psi\) reduces to zero. \(\psi\rightarrow 0\) as \(x\rightarrow 0\).
Is the size of an electron the same anywhere in the universe?
