v2t+v2s=A−Bds(x)
v2t+v2s=c2−(c2−c2n2)ds(x)
And that in an uniform photon-speed-slowing medium,
vs=cn.sinθ
where θ=sin−1√1−noc2
From the energy conservation equation,
v2t+v2s=c2n2, if vs=cn.sinθ then,
v2t=c2n2(1−sin2θ)=(cn.cosθ)2
vt=cn.cosθ
where cosθ is given by √noc and no is related to the refractive index of the medium by
no=c2(1−1n2)
Obviously,
vtc=γ=1ncosθ=1n√1−1n2
where n is the refractive index of the medium slowing photons down. A photon that passing through a medium that slow it down in space also experiences time dilation. Photons begin to experience time in the denser medium. Denser space is an optically denser medium as far as a photon is concern.
Vc=cn(sinθ+i.cosθ), that
vs=Re[cn(sinθ+i.cosθ)] and
vt=Im[cn(sinθ+i.cosθ)]
In other words,
Vc=vs+ivt
where the real part is space and the imaginary part is time. And that space and time is orthogonal.