If, temperatue,
\(T^2=T^2_c+T^2_g\)
and
\(T_c=\cfrac{1}{2}qv^2_{rc}\)
\(T_g=\cfrac{1}{2}mv^2_{rg}\)
then,
\(T^2=\cfrac{1}{4}(q^2v^4_{rc}+m^2v^4_{rg})\)
If the above is valid, a matter/antimatter collision along the charge time axis
\(qv_{tc} + q(-v_{tc}) = 0\)
that results in a release of energy,
\(\Delta E=2qv^2_{tc}\)
The temperature component about the charge time axis changes by,
\(\Delta T_c=\Delta E=2qv^2_{tc}\)
and in total,
\(2T\Delta T=2T_c\Delta T_c+2T_g\Delta T_g\)
\(\Delta T=\cfrac{1}{T}(T_c\Delta T_c+T_g\Delta T_g)\)
\(\Delta T=\cfrac{1}{T}T_c\Delta T_c\) \(\because \Delta T_g=0\)
where \(q\), and \(v_{tc}\) are constants, \(v_{rc}\) increases with increasing temperature.
The last expression suggest that the temperature of plasma has a underlying variable-squared dependence. In this case,
\(\Delta T=q^2v^2_{tc}.x^2\) where \(x=v_{rc}\)
And the expression also implies that at high plasma temperature when more of the contribution to \(T\) is due to \(T_c\),
\(T\approx T_c\) then,
\(\because \cfrac{T_c}{T}\approx 1\)
\(\Delta T\approx 2qv^2_{tc}\) --- (*)
the change in temperature is roughly a constant, given an overall constant collision rate.
All these are hypothetical. Temperature has actually been redefined as a energy term; no longer a potential term. The rotational quantities, \(v_{rc}\) and \(v_{rg}\) are not measurable immediately. It is not surprising that the expression (*) allows \(v_{tc}\), time speed along the charge time axis, to be estimated. By symmetry, since the axes are assigned arbitrarily, \(v_{tc}=v_{tg}\), time speed along the gravitation time axis is the same as time speed along the charge time axis. There no reason for the two time speeds to be different. With \(v_{tc}\), it is then possible to estimate \(v_{rc}\), the rotational velocity of the charge time axis using (**). Both estimates, \(v_{tc}\) and \(v_{rc}\), can possibly be derived from the same plasma temperature vs time curve, obtained at a constant collision/annihilation rate. This rotational value, \(v_{rc}\), is not equal to \(v_{rg}\); the temperature associated with each time axis can be different. Evetually these two temperatures/rotations/spins might equalized, as already there is a mechanism by which the axes transfer energy (conservation of energy).
Please remember all these are hypothetical.
