Hold Your Horses

There is a problem normalizing $q$ charge and $m$ mass.

$(v^2_t+v^2_s+v^2_{rg})+(v^2_{tc}+v^2_c+v^2_{rc})=c^2$ may also be wrong for the same reason.

We should have instead.

$(mv^2_t+\cfrac{1}{2}mv^2_s+\cfrac{1}{2}mv^2_{rg})+(qv^2_{tc}+\cfrac{1}{2}qv^2_c+\cfrac{1}{2}qv^2_{rc})=c^2$

where $c^2$ still  represent a constant.

The kinetic energies along the time dimensions are without the factor $\cfrac{1}{2}$ (From the post "No Poetry for Einstein").  In the case of,  $g$ the factor $G_o$ took care of this discrepancies.  Both  $g_{rc}$ and  $g_{rg}$ also accounted for the value of 2.

Hold you horses!  And if however, numerically,

$|q|=m$

for a basic charge, and then with changes made to the value of $\varepsilon_o$ and $G_o$.  We would still have a valid system of equations.

Early posts are still correct as constants   $G_o$   and   $\varepsilon_o$ absorbed the discrepant value of 2.

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