Friday, August 1, 2014

Hold Your Horses

There is a problem normalizing \(q\) charge and \(m\) mass.

\((v^2_t+v^2_s+v^2_{rg})+(v^2_{tc}+v^2_c+v^2_{rc})=c^2\) may also be wrong for the same reason.

We should have instead.

\((mv^2_t+\cfrac{1}{2}mv^2_s+\cfrac{1}{2}mv^2_{rg})+(qv^2_{tc}+\cfrac{1}{2}qv^2_c+\cfrac{1}{2}qv^2_{rc})=c^2\)

where \(c^2\) still  represent a constant.

The kinetic energies along the time dimensions are without the factor \(\cfrac{1}{2}\) (From the post "No Poetry for Einstein").  In the case of,  \(g\) the factor \(G_o\) took care of this discrepancies.  Both  \(g_{rc}\) and  \(g_{rg}\) also accounted for the value of 2.

Hold you horses!  And if however, numerically,

\(|q|=m\)

for a basic charge, and then with changes made to the value of \(\varepsilon_o\) and \(G_o\).  We would still have a valid system of equations.

Early posts are still correct as constants   \(G_o\)   and   \(\varepsilon_o\) absorbed the discrepant value of 2.

: )\(\ni\)