There is a problem, if
\(\Delta t=\cfrac{v}{c}-1\)
when \(v=0\)
\(\Delta t=-1\)
when \(v=c\)
\(\Delta t=0\)
However near the equator, earth's motion is about \(460\,ms^{-1}\). In one second, earth has moved \(460\,m\). This means collapsed photon returning from one second in the future is \(460\,m\) away from the present position. The argument here for X ray penetration is that the photons materialize inside the object just in front of the X ray source, through a space of about \(0.2\,m\). This requires,
\(\Delta t=\cfrac{0.2}{460}=4.35\text{e-4}\,s\)
This requires \(v\) to be nearer to \(c\).
We should have used,
\(\Delta t=\cfrac{v}{c}\)
instead, taking \(c\) as reference,
\(\cfrac{S_{p\,Cu}}{S_{p\,H_2}}=\cfrac{\cfrac{v_{boom\,Cu}}{c}}{\cfrac{v_{boom\,H_2}}{c}}\)
\(S_{p\,H_2}=\cfrac{v_{boom\,H_2}}{v_{boom\,Cu}}*S_{p\,Cu}\)
\(S_{p\,H_2}=\cfrac{0.154}{1061.42}*0.2=2.902\text{e-5}\,m\)
X ray using Hydrogen gas (\(H_2\)), penetrates only \(30\,\mu m\). Either a very thin anode of less than thirty micron is used followed immediately by the object elements, or another element should be used to generate X ray in the posts "Probing The Nucleus" and "Probing Sideways" both dated 19 Jan 2018.
Better yet, without an anode at all. A thin object film placed at \(S_p\) (from the post "Quantifying Time Travel Backwards" dated 20 Jan 2018), without an intervening anode.
