Wednesday, January 17, 2018

Finding Nemo

Finding \(a_{\psi\,ne}\) in light dispersion...

still looking...

where's Nemo?

My guess is,


\(\lambda_{ne}=460\,nm\),  which is also the solar irradiance peak.

 \(a_{\psi\,ne}=\cfrac{\lambda_{ne}}{2\pi}=\cfrac{460*10^{-9}}{2\pi}=7.321\text{e-8}\,m\)

 \(a_{\psi\,ne}=7.321\text{e-8}\,m\)

Have a sunny day.