\(v_{boom}=3.4354*\cfrac{density}{Z}=3.4354*\cfrac{2340}{5}=1607.80\,ms^{-1}\)
\(S_{p\,B}=\cfrac{1607.8}{1061.42}*0.2=0.303\,m\)
This is the most penetrating X ray using Boron \(B\), at \(30\,cm\).
\(V_{min}=\cfrac{1}{2}\cfrac{M}{qN_A}\left(3.4354*\cfrac{density}{Z}\right)^2\)
\(V_{min}=\cfrac{1}{2}*\cfrac{10.806}{6.0221*10^{23}*1.6021*10^{-19}*10^{3}}*\left(3.4354*\cfrac{2340}{5}\right)^2\)
\(V_{min}=0.1445\,V\)
For a length of \(d=10\,cm\),
\(v_{min}=\cfrac{0.1445}{0.1}=1.445\,V\)
Compare this to copper \(Cu\) of density \(8960\,kgm^{-3}\),
\(V_{min}=\cfrac{1}{2}*\cfrac{63.546}{6.0221*10^{23}*1.6021*10^{-19}*10^{3}}*\left(3.4354*\cfrac{8960}{29}\right)^2\)
\(V_{min}=0.3710\,V\)
For a length of \(d=10\,cm\),
\(v_{min}=\cfrac{0.371}{0.1}=3.71\,V\)
Both \(v_{min}\) are resonance value, only at exactly these values are X rays emitted.
The value of \(V_{min}\) for copper however, does not compare with the post "X Ray, Inner Electron Cloud And Just As Shocking TWO" dated 15 Oct 2017, where,
\(I_{res}=1.1974 A\)
because the electric resistance of copper is very low at \(16.78 nΩ·m\).
Given a voltage of \(3.71\,V\), the current need not be at \(I_{res}=1.1974\,A\) unless the cross sectional area of the wire is at,
\(V=3.71=1.1974*16.78*10^{-9}*\cfrac{0.1}{A_x}\)
\(A_x=1.1974*16.78*10^{-9}*\cfrac{0.1}{3.71}=5.41\text{e-10}\,m^2\)
The electron cloud at resonance and colliding particles at \(v_{boom}\) are different phenomenon. It may not be correct to associate them.
Then again \(v_{min}\) for a solid has never been verified. How much free space is there, within a solid, to accommodate basic particles?
Good night.
