Friday, July 11, 2014

A Pointy Wire...

Since, resistance \(R\) is inversely proportional to cross section area \(A\),

\(R\propto \cfrac{1}{A}\)

We let,

\(R=\cfrac{k}{\pi r^2}\)    where \(k\) is a constant of proportionality.

If \(r=\sqrt{\cfrac{d}{x}}\) then

\(R=\cfrac{k}{\pi d}.x\)

then

\(V=IR=I\cfrac{k}{\pi d}.x\)

In which case,

\(E=\cfrac{V}{d}=I\cfrac{k}{\pi d^2}.x\)

Given a constant \(I\),

\(E=D\cfrac{V}{d^2}.x\)

where \(D=\cfrac{k}{R\pi }\) is a constant and \(R\) is the total resistance of the wire.

A plot of \(r=\sqrt{\cfrac{d}{x}}\) is given below, the actual function plotted is (10/x)^(1/2), with d =10,


This graph is rotated about the x-axis to generate a solid that is the antenna.  Since the driving signal \(V\) is sinusoidal, it can be applied to the boarder end all the same.