Anti Gravity, Mechanically Yours

From the Post "Anti Gravity", the expression for lift is given by,

$F_l=\rho\pi a^2_o(2v^2-\frac{1}{2}g\pi r_o)$

Smaller $r_o$ provides greater lift, as such it may be better to break one big curve into smaller curves as shown.

Anti Gravity II

Although we see that the main contribution to lift is still $v$ the velocity with which the fluid is moving through the tube.

In this case, the total lift is $16*F_l$.