Hollow Metal

From the post "Shaking In The Infra Red" dated 24 Dec 2018, we have for the case of iron, $Fe$,
metallic bond size of,

$a_{\psi}=126\,pm$

from which

$f_{osc}=c\sqrt{\cfrac{2\pi}{(126*10^{-12})}}=6.6946e13\,Hz$

If we were to deliver energy by the impact of electrons,

$I_{osc}=q_e*f_{osc}=1.602176565\text{e-19}*6.6946e13=1.07259\text{e-5}\,A\approx10.7\,\mu A$

What will happen?  What is the nature of $f_{osc}$ resonance?

And for aluminium $Al$,

$f_{osc}=c\sqrt{\cfrac{2\pi}{(143*10^{-12})}}=6.2841e13\,Hz$

$I_{osc}=q_e*f_{osc}=1.602176565\text{e-19}*6.2841e13=1.007\text{e-5}\,A\approx10.1\,\mu A$

Does the metal turn transparent when $I_{osc}$ passes through it?  It is difficult to image the metal turning red hot at such low current level.  With a hole in the middle of each constituent atom, the metal may just be hollow.

Good night...