Saturday, December 29, 2018

Hollow Metal

From the post "Shaking In The Infra Red" dated 24 Dec 2018, we have for the case of iron, \(Fe\),
metallic bond size of,

\(a_{\psi}=126\,pm\)

from which

\(f_{osc}=c\sqrt{\cfrac{2\pi}{(126*10^{-12})}}=6.6946e13\,Hz\)

If we were to deliver energy by the impact of electrons,

\(I_{osc}=q_e*f_{osc}=1.602176565\text{e-19}*6.6946e13=1.07259\text{e-5}\,A\approx10.7\,\mu A\)

What will happen?  What is the nature of \(f_{osc}\) resonance?

And for aluminium \(Al\),

\(f_{osc}=c\sqrt{\cfrac{2\pi}{(143*10^{-12})}}=6.2841e13\,Hz\)

\(I_{osc}=q_e*f_{osc}=1.602176565\text{e-19}*6.2841e13=1.007\text{e-5}\,A\approx10.1\,\mu A\)

Does the metal turn transparent when \(I_{osc}\) passes through it?  It is difficult to image the metal turning red hot at such low current level.  With a hole in the middle of each constituent atom, the metal may just be hollow.

Good night...