From the post "What If The Particles Are Photons?" dated 12 Dec 2017, where we have a factor of \(10^6\) in \(\lambda\), in either
\(\lambda=10^6\)
or
\(\lambda=1.0678825790017675793e6\)
and in the post "I Don't Know..." also dated 12 Dec 2017, where in the time dimension, we considered a spherical volume of,
\(Vol_{time}=\cfrac{4}{3}\pi T^3=\cfrac{4}{3}\pi* \cfrac{1}{f^3}\)
and introduced a factor of \(\cfrac{4}{3}\pi\). Both factors taken together, we have
\(\mu_t=\cfrac{4}{3}\pi\times10^{6}\)
or
\(\mu_t=\cfrac{10}{3}*4\pi\times10^{7}\)
and we compare this with
\(\mu_o=4\pi\times10^{-7}\)
The factor \(10^{-7}\) adjusts for the the factor \(10^{6}\) needed in \(\lambda\). Leaving behind \(\cfrac{10}{3}\). That means we are measuring in \(10^{6}\) as \(1\). \(4\pi\) cancels from the denominator.
Now, where is the post with the factor \(\cfrac{10}{3}\)? It was a post to calculate \(G\)...
In any case, the a factor of \(\cfrac{10}{3}\) is unaccounted for.
Good day.
Note: If we take the reciprocal of \(\lambda=1.0678825790017675793e6\)
\(\cfrac{1}{\lambda}=9.364325438...\times10^{-7}\)
and we divide this by \(\pi\)
\(\cfrac{1}{\lambda}*\cfrac{1}{\pi}=2.981\times10^{-7}\)
ie. \(\cfrac{1}{\lambda}\approx3\pi\times10^{-7}\) or
\(\cfrac{1}{\lambda}\approx\cfrac{3}{4}\mu_o\)
with \(\mu_o\) defined as \(4\pi\times10^{-7}\)
OK?
In fact with \(f=\cfrac{c}{\lambda}=\cfrac{8^3}{18}\pi^2\) ,
\(\cfrac{1}{\lambda}=\cfrac{3}{4}\mu_o\) exactly, when \(c=\cfrac{8^3}{54}\pi\times10^{7}=297869525\)
and we are going round and round...
