μ2μ1=tan(θ2−α2s)tan(θ1−α)=tan(θ2+α2p)tan(θ1+α)
tan(θ2−α2s)=μ2μ1tan(θ1−α)
from which we may obtain α2s. And
tan(θ2+α2p)=μ2μ1tan(θ1+α)
from which we may obtain α2p.
And θ2 is given by,
tan(θ1)tan(θ2)=ε2ε1
from the post "A Bloom Crosses Over" dated 10 Aug 2015.
The graph illustrates how to obtain α2s and α2p.