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Monday, August 10, 2015

Split Cannot Mend

Consider this,

μ2μ1=tan(θ2α2s)tan(θ1α)=tan(θ2+α2p)tan(θ1+α)

tan(θ2α2s)=μ2μ1tan(θ1α)

from which we may obtain α2s.  And

tan(θ2+α2p)=μ2μ1tan(θ1+α)

from which we may obtain α2p.

And θ2 is given by,

tan(θ1)tan(θ2)=ε2ε1

from the post "A Bloom Crosses Over" dated 10 Aug 2015.


The graph illustrates how to obtain α2s and α2p.