The smaller the particle the higher EnEn is. Big particle absorb energy to break into smaller particles. When small particles coalesce energy is released as a photon that we observe as the emission spectrum.
Big particles are more susceptible to collision impacts and break into smaller particles, absorbing part of the energy of impact on breaking up. Energy is absorbed as a photon, from which we obtain the absorption spectrum.
But En is not ψ. En is the result of ψ on a circular path at light speed c.
So,
λψ≠λn
and the photon packets emitted or absorbed,
h.fvis=h.(fn1−fn2)
λvis=cfvis=cfn1−fn2
where fvis and λvis are obtained from the experimental spectrum(s) observed.
Obviously,
λvis≠λn and
λvis≠λψ
But,
λψn=λn, m=1
only when m=1 that there is one wavelength around the circular path of radius aψ. The factor 2π appears as the wavelength, λψ is wrapped around a circular path.
And since the energy transitions as particles coalesce and disintegrate is the reverse of electron energy level transitions, we do not have an issue with negative energy.
And in the rest state of no collisions, we have aψn=1 where aψ is the smallest at the highest energy possible,
En=1=Emax
aψ=aψ1=aψc
So, paradoxically ψ with aψc has the highest energy but the smallest size.