Tuesday, October 18, 2016

Particles In Orbits

The difference plot of the expression, \(\cfrac { \sqrt [ 3 ]{ n_{ 2 } } -\sqrt [ 3 ]{ n_{ 1 } }  }{ \sqrt [ 3 ]{ n_{ 1 }n_{ 2 } }  } -\cfrac { n_{ 2 }^{ 2 }-n_{ 1 }^{ 2 } }{ (n_{ 1 }n_{ 2 })^{ 2 } }\)


however, draws a sense of déjà vu...

The concepts leading to the expression \(\cfrac { \sqrt [ 3 ]{ n_{ 2 } } -\sqrt [ 3 ]{ n_{ 1 } }  }{ \sqrt [ 3 ]{ n_{ 1 }n_{ 2 } }  }\) reverses the energy sign of conventional electron energy level transitions; \(E_{1\rightarrow 2}\) is negative and the particle loses energy.  \(E_{1\rightarrow 2}\) is emitted

This would make the plot for \(n_1=1\) in the above graph, an absorption line.

For all values of \(n_2\), only when \(n_1=1\) is an absorption line.  The plots in black are emission lines against which we see the absorption line without direct illuminations.

Values of the plots in black below \(y=0\) is ignored because \(n_2\ge n_1\).

Rydberg constant is not murdered, instead a new process is given birth.

\(\cfrac { \sqrt [ 3 ]{ n_{ 2 } } -\sqrt [ 3 ]{ n_{ 1 } }  }{ \sqrt [ 3 ]{ n_{ 1 }n_{ 2 } }  }\) occurs at the same time as \(\cfrac { n_{ 2 }^{ 2 }-n_{ 1 }^{ 2 } }{ (n_{ 1 }n_{ 2 })^{ 2 } }\) due to quantized energy levels in Bohr model theory.  The two process has reverse energy signs and hence married with a negative sign.  According to Bohr model \(E_{1\rightarrow 2}\) is positive and the particle gains energy and transits to a higher energy level.

We have instead,

\(\Delta E_{2\rightarrow 1}=h.f_{\psi\,c}\left(\cfrac{\sqrt[3]{n_2}-\sqrt[3]{n_1}}{\sqrt[3]{n_1n_2}}-\cfrac { n_{ o2 }^{ 2 }-n_{ o1 }^{ 2 } }{ (n_{o1 }n_{ o2 })^{ 2 } }\right)\)

where a change \(n_1\rightarrow n_2\) is accompanied by a change in orbital energy level \(n_{o1}\rightarrow n_{o2}\).

Only now are the particles in orbits.

Note:  \(E_2=E_1+\Delta E_{1\rightarrow 2}\)