Both these particles impart electric potential energy,
A bold guess is that electron that also carries heat and has low mass is the left particle and proton is the right particle, where \(t_g\) manifest itself perpendicular to two parallel, current carrying wires. They are not equivalent.
So, what's is the difference between existing in the \(t_g\) time dimension, as in the case of the electron, and being a wave along \(t_g\), as like a proton?
Energy in the wave can be dissipated and reduced, the particle still exist. Energy that marks the particle existence (\(E=mc^2\)) cannot be dissipated, the particle disappears from existence if that happens.
The space dimensions are curled along the time dimensions \(t_g\) and \(t_T\) respectively. The \(x_1\)s in the diagram are 90o apart. When we align the two waves such that the time dimensions, \(t_c\) and \(t_g\) are parallel, we find that \(x_1\) for the case of proton is going down \(-t_T\) with respect to the electron's \(+t_T\) time axis. (After note: Why is \(x_1\) not along \(t_g\) instead?? It does not matter here, as long as \(x_1\) is in negative time, the force will have an opposite sign. The time dimensions, \(t_c\), \(t_g\) and \(t_T\) are not differentiated as far as our senses are concerned. However, this could just be a graphical trick as a result of the right hand screw rule. More convincing proof is needed.) This is consistent with the fact that the charges have opposite force fields.
If this model is true, then electron give heat but not gravitational potential energy and proton gives gravitation potential energy but not heat; in addition to the electrical fields around them. Energy oscillating between \(t_c\) and \(x_1\) forms the electrical field. Energy along \(t_g\) or \(t_T\), that is the kinetic energy of the wave, is extracted by collisions.
So a proton beam will give you a positive light feeling. Have a nice day and plenty of eternal sunshine!
