Wednesday, May 20, 2015

Brownian Motion, Short Time Travel, O particles

Then we come to the mistake I have made,

What are these?

We experience \(t_c\), \(t_g\) and \(t_T\) as a whole, just as in any direction space is just \(x\); then \(t_c\), \(t_g\) and \(t_T\) are undifferentiated and so are these particles.  However, if our sight is a charge phenomenon (along \(t_c\) only) then \(o_{t_T}\)(\(x\),\(t_c\),\(t_g\)) and \(o_{t_g}\)(\(x\),\(t_c\),\(t_T\)) can impart energy along \(t_c\) and maybe slow/speedup \(p_{t_c}\) and induce invisibility.  The notation \(o_{t_x}\) is used here.

These O particles can still affect the space dimensions via the space-time energy oscillations in photons.   And can couple energy directly onto the time dimension.  Indirectly, they require a photon or a basic particle to be detected in space.  In the case of the left most O particle in the diagram, \(p_{t_T}\)(\(x_1\),\(x_2\),\(t_g\)), \(p_{t_T}\)(\(x_1\),\(x_2\),\(t_c\)), \(p_{t_c}\)(\(x_1\),\(x_2\),\(t_g\)) or \(p_{t_g}\)(\(x_1\),\(x_2\),\(t_c\)); photons with energy oscillating in either \(t_g\) or \(t_c\) time dimension and a space dimension, or a stationary basic particle where the first entry inside the parenthesis is replaced with a time dimension and has energy oscillation between \(t_c\) or \(t_g\) and a space dimension.  That is, \(q\)(\(t_T\),\(x\),\(t_g\)), \(T\)(\(t_c\),\(x\),\(t_g\)), \(T\)(\(t_g\),\(x\),\(t_c\)) and \(g\)(\(t_T\),\(x\),\(t_c\)).

OK?!