The problem in dealing with time is that all time measurement must be based on a standard second. At different time speed however, the measured time duration is different over 1 second.
At time speed v which is less that normal time speed c,
\(v.1 = { t }_{ v }\)
At normal time speed, c
\(c.1 = { t }_{ c }\)
Both v and c are velocities defined as
\({ v, c } = \cfrac { d{ x } }{ d{ t }_{ c } }\)
which are then velocities defined at time speed c. And so we have this relationship
\(\cfrac { c }{ v } =\cfrac { { t }_{ c } }{ { t }_{ v } } \quad ,\quad \cfrac { c }{ v } .\cfrac { 1 }{ d{ t }_{ c } } =\cfrac { 1 }{ d{ t }_{ v } }\)
Consider, the work done equation as applied to a mass m, along the time dimension.
\(E=\int { { F }_{ v }dx }\) and that force is the rate of change of momentum
\({ F }_{ v }=\cfrac { d{ P }_{ v } }{ d{ t }_{ v } } =\cfrac { mdv }{ d{ t }_{ v } }\)
Notice the expression is \(d{ t }_{ v }\), this is to say a person will still observe the same fact that, force is the rate of of change momentum no matter what time speed he is travelling at. In order to derive a consistent expression however, we will need to change \(d{ t }_{ v }\) to \(d{ t }_{ c }\), as we observe the universe travelling at time speed c.
Till the next post.