Space Density and Gravity

Let's assume that the speed of time is some terminal velocity in space of density  ${ d }_{ s }$ and that all factors are constant except for  ${ d }_{ s }$.  We have

 ${ v }_{ t }^{ 2 }\propto \cfrac { 1 }{ { d }_{ s } }$  this is an assumption.

But, if  we let,

${ v }_{ t }^{ 2 }=\quad \cfrac { A }{ { d }_{ s } }$ where A is a constant

then

 $g=-\cfrac { 1 }{ 2 } .\cfrac { d{ v }_{ t }^{ 2 } }{ dx } =-\cfrac { 1 }{ 2 } .\cfrac { d }{ dx } (\cfrac { A }{ { d }_{ s } } )=\cfrac { A }{ 2 } .\cfrac { 1 }{ { d }_{ s }^{ 2 } } .\cfrac { d{ d }_{ s } }{ dx }$

assume further that space is compressed linearly, where $x=0$ has the highest compression ${ a }_{ 0 }-a{ r }_{ 0 }$, and the equation is valid up to ${ d }_{ s }=0$ or some residue value  ${ d }_{ o }$ not negative.

${ d }_{ s }=-a(x+{ r }_{ 0 })+{ a }_{ 0 },\quad \cfrac { d{ d }_{ s } }{ dx } =-a$

then

$g=-G.\cfrac { 1 }{ { (-a(x+{ r }_{ 0 })+{ a }_{ 0 }) }^{ 2 } }$ where all constants have been grouped into G. This equation shows that gravity is directed at x=0 where space is most compressed and that the inverse square law effect applies assuming that space compresses linearly.  Space will be compressed around a massive body or be artificially compressed by moving space towards one end.