The good thing about deriving gravity g, with any other mass is that it leaves room for anti-gravity without using massive bodies. You can experience zero gravity without the need for a mass the size of this planet.
From previously,
\(g=-\cfrac { 1 }{ 2 } .\cfrac { d{ E }_{ m } }{ dx }\),
where
\({ E }_{ m }=\cfrac { E }{ m }\) is the conservative field expressed as per unit mass.
but
\(\cfrac { E }{ m } ={ v }_{ t }^{ 2 }\) from \(E=m{ c }^{ 2 }\)
as such
\(g=-\cfrac { 1 }{ 2 } .\cfrac { d{ v }_{ t }^{ 2 } }{ dx }\)
which means that under different gravity g, time speed is different, to be precise, the differential of the square of time speed over distance is different.
