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Monday, October 16, 2017

To Assume Not Much

In the post "X Ray, Inner Electron Cloud And Just As Shocking TWO" dated 15 Oct 2017, the expression,

N.2πaψ=λβ

was formulated before aψc was discovered. We might have,

3N.2πaψc=λβ  

from,

31N=aψcaψN

and so,

ave.EαEβ=3N+1N

From which we may find aψc, but for the resonance of the electron cloud that we seek, we need the electron cloud aψcloud,

not  3N.aψc   nor   aψc

The rationale for making the estimate N and N+1 is that given,

N.2πaψ=λβ

and

(N+1)2πaψ=λaveα

no matter what aψ is, the addition of one more particle pushes aψ outwards and the allowable energy states splits into two narrowly spaced energy states.  When the resonance frequency is applied using an appropriate current, the particles injected resonate.  X-ray radiations at the Eα values will dominate and is adjusted as the current is reduced by an integer divisor.

This way, there is no need to assume that aψ=aψc.  The only assumption is that the Eα's and Eβ are consecutive, due to the injection and emission of one particle aψ.

Furthermore,

N.2πaψ=λβ

(N+1)2πaψ=λaveα

(λβ2πaψ+1)2πaψ=λaveα

λβ+2πaψ=λaveα

If f1m (the approximation part) such that,

m.f=constant

mβc.fβ.λβ+mψc.fψ.2πaψ=(mβ+mψ)c.faveα.λaveα

that the total work done in going around λβ and around the additional particle aψ, is the work done going around λaveα.

Goodnight.