This is why they are squares in rational right angle triangle,
\(\cfrac{1}{2}*\cfrac{204}{3}*\cfrac{6}{3}=68=2*2*17\)
the squares comes from multiple factors, in this case \(2*2\).
Note: \({\cfrac{204}{3},\,\cfrac{6}{3}}\) also work for an area of 51 which has no square and so squareless.
