This does work because it seem that one \(q\) fits all, \(n_{j}\), \(n_{j+1}\)...
There seems to be no simple math problem now. But maybe all higher composite numbers share all factors, prime or otherwise, from lower composite numbers, as the graph above suggests.
They do, but is just \(2\) for the series \(2n_{j}\), \(2n_{j+1}\)...
