Thursday, August 17, 2017

Magnetic Bonds And Stir

And a string of "maybe"s leads to,


Given its high symmetry, this is likely the quasi-nucleus that loses its orbiting electrons, acquire a layer of \(g^{+}\) particles that bonds by sharing \(g^{-}\) particles and forms into a crystal lattice.



Does it stop here?  The likely release of \(T^{-}\) particle when the crystal collapse suggests another \(T^{+}\) layer is attracted to the quasi-nucleus and that the crystal are held together by \(T^{-}\)--\(T^{+}\) bonds instead of \(g^{-}\)--\(g^{+}\) bonds proposed previously.  \(T^{-}\)--\(T^{+}\) will be seen as magnetic in nature.

Bonding with \(T^{-}\) particles complement the charge on the quasi-nucleus and prevents the next \(p^{+}\) layer.

Maybe, but Good Morning!