Gems, Gravity Particles Bonds And Earthquakes

My mind is failing but...

Remember the tuple ($g^{+}$, $T^{+}$, $p^{+}$) that was used as a nucleus cyclic set to build up a nucleus by stripping the associated atom of its negative charges and allow the weak fields from the orbiting positive charges to attract $g^{+}$ particles, the first member of the next layer making up a nucleus?

Well, because gem stones are relatively stable in temperature, it is unlikely that the bonds holding their crystalline structure involve $T^{-}$ particles.  If $T^{-}$ particles forms bonds, such bonds will interact with $T^{+}$ and $T^{-}$ particles just as chemical bonds are formed and broken with a supply of positive and negative charges during electrolysis.

It is more likely that, for example Amethyst, the molecule $SiO_2$ is stripped of its outer electrons and the bare paired proton orbits generate weak gravitational fields that attract a layer of  $g^{+}$ particles.  The stripped $SiO_2$ molecules with a valid Quantum Number forms a quasi-nucleus, over which $g^{+}$ particles are in orbits balanced by $g^{-}$ particles.  It is the bonding of $g^{+}$ and $g^{-}$ particles (the equivalent of covalent bonds when $p^{+}$ shares $e^{-}$ particles), that buildup the crystal.

Since, both $g^{+}$ and $g^{-}$ particles are involved, gem stones are rare unless environmental conditions provides for these types of particles.  Since, $g^{+}$ pulls you up and $g^{-}$ sets you down, earthquakes zones have an abundance of both these particles.  From the post dated 12 May 2016, "Seven Up!", where negative charges are removed from $Cu$ to form a crystal lattice, in a similar way, an abundance of both $g^{+}$ and $g^{-}$ particles initially buildups a quasi-nucleus around a stripped $SiO_2$ and then a depletion in $g^{-}$ particles is needed to form crystals.

Which would lead us to earthquakes as longitudinal waves of $g^{+}$ and $g^{-}$ particles passing through earth's crust.

But wait, maybe a diagram to show how $SiO_2$ forms a nucleus is in order.   It is just like $CO_2$ with $C$ replaced by $Si$.  Why not then a $CO_2$ gem?  It could be that $C$ is too small to accommodate the two $O$s into its fold to form a quasi-nucleus.  $Si$ being bigger, both $O$s can approach closer where the particles orbits overlaps and form a distorted spherical entity that acts like a nucleus over which a $g^{+}$ layer forms.

The presence of the $g^{+}$ layer will add mass to the crystal.  When a crystal disintegrate with the release of gravity particles and the addition of $e^{-}$ particles, its mass should also change.  We may isolate gravity particles and find their masses from crushing crystals with a dash of electrons.

Good night.