Remember the tuple (\(g^{+}\), \(T^{+}\), \(p^{+}\)) that was used as a nucleus cyclic set to build up a nucleus by stripping the associated atom of its negative charges and allow the weak fields from the orbiting positive charges to attract \(g^{+}\) particles, the first member of the next layer making up a nucleus?
Well, because gem stones are relatively stable in temperature, it is unlikely that the bonds holding their crystalline structure involve \(T^{-}\) particles. If \(T^{-}\) particles forms bonds, such bonds will interact with \(T^{+}\) and \(T^{-}\) particles just as chemical bonds are formed and broken with a supply of positive and negative charges during electrolysis.
It is more likely that, for example Amethyst, the molecule \(SiO_2\) is stripped of its outer electrons and the bare paired proton orbits generate weak gravitational fields that attract a layer of \(g^{+}\) particles. The stripped \(SiO_2\) molecules with a valid Quantum Number forms a quasi-nucleus, over which \(g^{+}\) particles are in orbits balanced by \(g^{-}\) particles. It is the bonding of \(g^{+}\) and \(g^{-}\) particles (the equivalent of covalent bonds when \(p^{+}\) shares \(e^{-}\) particles), that buildup the crystal.
Since, both \(g^{+}\) and \(g^{-}\) particles are involved, gem stones are rare unless environmental conditions provides for these types of particles. Since, \(g^{+}\) pulls you up and \(g^{-}\) sets you down, earthquakes zones have an abundance of both these particles. From the post dated 12 May 2016, "Seven Up!", where negative charges are removed from \(Cu\) to form a crystal lattice, in a similar way, an abundance of both \(g^{+}\) and \(g^{-}\) particles initially buildups a quasi-nucleus around a stripped \(SiO_2\) and then a depletion in \(g^{-}\) particles is needed to form crystals.
But wait, maybe a diagram to show how \(SiO_2\) forms a nucleus is in order. It is just like \(CO_2\) with \(C\) replaced by \(Si\). Why not then a \(CO_2\) gem? It could be that \(C\) is too small to accommodate the two \(O\)s into its fold to form a quasi-nucleus. \(Si\) being bigger, both \(O\)s can approach closer where the particles orbits overlaps and form a distorted spherical entity that acts like a nucleus over which a \(g^{+}\) layer forms.
The presence of the \(g^{+}\) layer will add mass to the crystal. When a crystal disintegrate with the release of gravity particles and the addition of \(e^{-}\) particles, its mass should also change. We may isolate gravity particles and find their masses from crushing crystals with a dash of electrons.
Good night.
