Friday, December 30, 2022

Average Proof Pigeon Can Do It,

 Divide a unit circle into \(n\) equal sector each of arc length \(\cfrac{1}{n}\), \(n\) runners occupy these \(n\) sections.  On average, one runner is in each section, and so, their average and possible consecutive distance for two consecutive runners along the path is \(\cfrac{1}{n}\).

This is true for all numbers of runners greater than \(3\), with constant distinct speeds.

And the lonely runner conjecture is proved.  No pigeonholes needed.