If you have a stiff right thumb, try listening to this,
Aflatoxin HC 438-74 Hz
twenty minutes or so. You should be able to flex your thumb without the clicking sound.
Here are the rest of the frequencies for aflatoxin,
Aflatoxin 344 Hz
Aflatoxin 474 Hz
Aflatoxin 476 Hz
Aflatoxin 510 Hz
Aflatoxin 568 Hz
Aflatoxin 943 Hz
Aflatoxin HC 466-01 Hz
Aflatoxin HC 8812-31 Hz
Aflatoxin HC 9359-97 Hz
Do not play 474, 476 and 466.01 Hz together. They form a low beat frequency. Only one of them at a time. And for good measure,
Influenzum toxicum 854 Hz
Been drinking water everyday, where did these toxins come from?
Sunday, April 26, 2020
Thursday, April 23, 2020
Just keep listening
Hundreds of years later, when the English language becomes cryptic, and someone digs up this blog from some antiquated archive might ask of the previous post,
"What Cucumber? Thick ones or thin ones?"
Just keep listening...
"What Cucumber? Thick ones or thin ones?"
Just keep listening...
Wednesday, April 22, 2020
What Cucumber?
If you wish to slim, this is one formula,
cucumber + coronavirus Rife frequencies 309.9 Hz, 1217.5 Hz and 1369.6 Hz
1~2 inches of cucumber, washed, sliced and raw, eaten at each meal. The frequencies are here coronavirus SARS 309-9_1217-5_1369-6 Hz
You can create the frequencies as mp3 using the program "Audacity", using Generate->(enter frequency), OK, File->Export, (enter file name), OK, Enter, OK.
As individual frequencies,
Coronavirus SARS 309-9 Hz
Coronavirus SARS 1217-5 Hz
Coronavirus SARS 1369-6 Hz
Use the frequencies by listening to it, daah. Use the VLC player. Change the preference to launch more than once instance at a time, so that all the frequencies can be played together, and loop the playering so that they play continuously for more than an hour.
This another set of coronavirus frequencies,
Coronaviridae Infections 182-5 Hz
Coronaviridae Infections 435-29 Hz
Coronaviridae Infections 562-5 Hz
Coronaviridae Infections 793-5 Hz
Coronaviridae Infections 995-75 Hz
You can download the files by left-clicking on the link, and click on the download icon on the top right of the resulting page.
Have a nice day,
cucumber + coronavirus Rife frequencies 309.9 Hz, 1217.5 Hz and 1369.6 Hz
1~2 inches of cucumber, washed, sliced and raw, eaten at each meal. The frequencies are here coronavirus SARS 309-9_1217-5_1369-6 Hz
You can create the frequencies as mp3 using the program "Audacity", using Generate->(enter frequency), OK, File->Export, (enter file name), OK, Enter, OK.
As individual frequencies,
Coronavirus SARS 309-9 Hz
Coronavirus SARS 1217-5 Hz
Coronavirus SARS 1369-6 Hz
Use the frequencies by listening to it, daah. Use the VLC player. Change the preference to launch more than once instance at a time, so that all the frequencies can be played together, and loop the playering so that they play continuously for more than an hour.
This another set of coronavirus frequencies,
Coronaviridae Infections 182-5 Hz
Coronaviridae Infections 435-29 Hz
Coronaviridae Infections 562-5 Hz
Coronaviridae Infections 793-5 Hz
Coronaviridae Infections 995-75 Hz
You can download the files by left-clicking on the link, and click on the download icon on the top right of the resulting page.
Have a nice day,
Sunday, April 19, 2020
且看《透天玄機》里的个样人种，
"人生毛角，壽延千百歲，不争不分，人物渾渾，從太古人也"
"人身長丈餘，壽延千至六七百歲，營巢穴居，無衣無食，次上古人也"
"人身長丈餘，壽延六百歲至三四百歲，有母無夫，物産始分，此中古之人"
"人身長八九尺，壽延一百三十歲，地平天成，五倫始判，此守息之人也"
"人身長五六尺，壽延百歲至七八十歲，有名有利,巧變百出，此奔波之人也"
"人長四五尺，壽研五六十歲至四十歲，嗔貪迷戀，禮樂喪失，此沉迷之人也"
"人長三四尺，壽延四五十歲，百事奸貪，并無法紀，此遭劫之人也"
"人長三四尺，壽延三四十歲，衣食颠倒，寒暑無時，此鬼形人也"
"人長二三尺，壽延三十歲，猶如一狗，出入畏懼，多黑少白，次蝼蟻之人也"
由此演变，
不争不分，人物渾渾\(\longrightarrow\)營巢穴居，無衣無食\(\longrightarrow\)有母無夫，物産始分\(\longrightarrow\)地平天成，五倫始判\(\longrightarrow\)有名有利,巧變百出\(\longrightarrow\)嗔貪迷戀，禮樂喪失\(\longrightarrow\)百事奸貪，并無法紀\(\longrightarrow\)衣食颠倒，寒暑無時\(\longrightarrow\)猶如一狗，出入畏懼，多黑少白
又，
太古人\(\longrightarrow\)次上古人\(\longrightarrow\)中古之人\(\longrightarrow\)守息之人\(\longrightarrow\)奔波之人\(\longrightarrow\)沉迷之人\(\longrightarrow\)遭劫之人\(\longrightarrow\)鬼形人\(\longrightarrow\)次蝼蟻之人
大多人会自认是 “奔波之人”， 但 “沉迷之人” 的成分也不少。从沉沦嗜乐，禮樂喪失变得 “百事奸貪，并無法紀”，结果人文尽灭，衣食不常，没有时季观念，再退化成 “如狗”。。。到此是结束灭亡，不是循环。 直至 “三元會辰，再生聖人” 才 “上上元甲子複來” 周而複始，循环不息。
完全被动！ 紫微降生也无能为力，逆此天运；灭族灭种。
"人生毛角，壽延千百歲，不争不分，人物渾渾，從太古人也"
"人身長丈餘，壽延千至六七百歲，營巢穴居，無衣無食，次上古人也"
"人身長丈餘，壽延六百歲至三四百歲，有母無夫，物産始分，此中古之人"
"人身長八九尺，壽延一百三十歲，地平天成，五倫始判，此守息之人也"
"人身長五六尺，壽延百歲至七八十歲，有名有利,巧變百出，此奔波之人也"
"人長四五尺，壽研五六十歲至四十歲，嗔貪迷戀，禮樂喪失，此沉迷之人也"
"人長三四尺，壽延四五十歲，百事奸貪，并無法紀，此遭劫之人也"
"人長三四尺，壽延三四十歲，衣食颠倒，寒暑無時，此鬼形人也"
"人長二三尺，壽延三十歲，猶如一狗，出入畏懼，多黑少白，次蝼蟻之人也"
由此演变，
不争不分，人物渾渾\(\longrightarrow\)營巢穴居，無衣無食\(\longrightarrow\)有母無夫，物産始分\(\longrightarrow\)地平天成，五倫始判\(\longrightarrow\)有名有利,巧變百出\(\longrightarrow\)嗔貪迷戀，禮樂喪失\(\longrightarrow\)百事奸貪，并無法紀\(\longrightarrow\)衣食颠倒，寒暑無時\(\longrightarrow\)猶如一狗，出入畏懼，多黑少白
又，
太古人\(\longrightarrow\)次上古人\(\longrightarrow\)中古之人\(\longrightarrow\)守息之人\(\longrightarrow\)奔波之人\(\longrightarrow\)沉迷之人\(\longrightarrow\)遭劫之人\(\longrightarrow\)鬼形人\(\longrightarrow\)次蝼蟻之人
大多人会自认是 “奔波之人”， 但 “沉迷之人” 的成分也不少。从沉沦嗜乐，禮樂喪失变得 “百事奸貪，并無法紀”，结果人文尽灭，衣食不常，没有时季观念，再退化成 “如狗”。。。到此是结束灭亡，不是循环。 直至 “三元會辰，再生聖人” 才 “上上元甲子複來” 周而複始，循环不息。
完全被动！ 紫微降生也无能为力，逆此天运；灭族灭种。
Saturday, April 18, 2020
Saturday, April 11, 2020
这绝对是迷信！
《透天玄機》
伯溫曰："紫微降生何方？"
道人曰："赤地沖天，地鳴山崩，牛生兩尾，日月并行，木上挂曲尺，即真主也。吳地黃冠，霞光萬道，旌禅下界，收留扶養，先有五瘟使者應此劫數，傳播瘟疫，人人皆遭難，烏梅可解，亂世妖人擡起首，有兩丁運馬，火虎出世，黑猿領兵，金槍出現，木鍾自鳴，爾乃登州指行，不可同行，侯赤氣沖天，方可制行，石人二眼，二人二足，乃起兵之時也。"
也许，不是这时候，不是这地方，不是这场瘟疫。。。但，文里很确切 “烏梅可解”。 （Prunus mume）。 是酸的还是甜的呀？
因为无从考证，这字迷怎么猜都可以，
赤地沖天 把“赤”字拆开
地鳴山崩 “地”是土， “地鸣” 土 里有个口，是“亮”字
牛生兩尾 “山崩”，“山”字倒斜，“生兩尾”，是“兴”字
日月并行 月往东行，在早上“日月并行”在东方，是“东”字
木上挂曲尺 是“朵”字，耳朵+东=“陈”，也可以是“阜”，也就是“阝”。
所以 “紫微降生” 是“陈兴亮”。是乌梅吃多了， 酸死了的“陈兴亮”。
娱乐而已，“天開一口任蹉跎”，莫迷莫。。。
注：
“先有五瘟使者應此劫數”， 紫微降生乃劫。
“尔” 二丁运马，首当先。
“石人二眼，二人二足” “硚”，制兵于四川，打得可真远。忍！忍！忍
《透天玄機》
伯溫曰："紫微降生何方？"
道人曰："赤地沖天，地鳴山崩，牛生兩尾，日月并行，木上挂曲尺，即真主也。吳地黃冠，霞光萬道，旌禅下界，收留扶養，先有五瘟使者應此劫數，傳播瘟疫，人人皆遭難，烏梅可解，亂世妖人擡起首，有兩丁運馬，火虎出世，黑猿領兵，金槍出現，木鍾自鳴，爾乃登州指行，不可同行，侯赤氣沖天，方可制行，石人二眼，二人二足，乃起兵之時也。"
也许，不是这时候，不是这地方，不是这场瘟疫。。。但，文里很确切 “烏梅可解”。 （Prunus mume）。 是酸的还是甜的呀？
因为无从考证，这字迷怎么猜都可以，
赤地沖天 把“赤”字拆开
地鳴山崩 “地”是土， “地鸣” 土 里有个口，是“亮”字
牛生兩尾 “山崩”，“山”字倒斜，“生兩尾”，是“兴”字
日月并行 月往东行，在早上“日月并行”在东方，是“东”字
木上挂曲尺 是“朵”字，耳朵+东=“陈”，也可以是“阜”，也就是“阝”。
所以 “紫微降生” 是“陈兴亮”。是乌梅吃多了， 酸死了的“陈兴亮”。
娱乐而已，“天開一口任蹉跎”，莫迷莫。。。
注：
“先有五瘟使者應此劫數”， 紫微降生乃劫。
“尔” 二丁运马，首当先。
“石人二眼，二人二足” “硚”，制兵于四川，打得可真远。忍！忍！忍
Brain Dead Finally
Disinfect home and work place.
Wear a mask in public.
Don't crowd.
Suck on herbal sweets or lozenges. Read this https://www.ncbi.nlm.nih.gov/pubmed/15889535 or this https://journals.sagepub.com/doi/pdf/10.1177/095632020501600205. Not too often, as long as you have the taste in your mouth, it is OK.
Refrain from touching anything in public.
Wash your hands the first thing you reach home or work place.
Get SARS - CoV-2 (CoVID-19) tested if you have to work with others.
If you are on the essential services list get your staff tested and start work.
Homes and work place should be well ventilated, do not close up entrances and exits that creates pockets of still air.
If you need a brain dead to give you SARS advice...
Wear a mask in public.
Don't crowd.
Suck on herbal sweets or lozenges. Read this https://www.ncbi.nlm.nih.gov/pubmed/15889535 or this https://journals.sagepub.com/doi/pdf/10.1177/095632020501600205. Not too often, as long as you have the taste in your mouth, it is OK.
Refrain from touching anything in public.
Wash your hands the first thing you reach home or work place.
Get SARS - CoV-2 (CoVID-19) tested if you have to work with others.
If you are on the essential services list get your staff tested and start work.
Homes and work place should be well ventilated, do not close up entrances and exits that creates pockets of still air.
If you need a brain dead to give you SARS advice...
Friday, April 10, 2020
Sunday, March 22, 2020
Ken
Hey, it's Kenny Rogers!
Thanks for your songs...
It is you
who bled their hearts through your songs
healing love loss and sorrows
It is you
It is you
It is you
who tore their hearts with your words
mending true loves forever
It is you
It is you
He remembered his friends and gave generously...
Thanks for your songs...
It is you
who bled their hearts through your songs
healing love loss and sorrows
It is you
It is you
It is you
who tore their hearts with your words
mending true loves forever
It is you
It is you
He remembered his friends and gave generously...
Thursday, March 19, 2020
Forgive But Remember
Is or is not, have or have not, we all take stock of what is and what we have now, carve a path into the future and move on.
It is good to have any sort of memory back, good ones and bad.
It is good to have any sort of memory back, good ones and bad.
Friday, February 7, 2020
Jumping Jack Not
This is a new way to multiply binaries,
This is exactly as the decimal multiply done previously.
Luckily, this is not a jumping jack; shifting bits is slower than sum.
Total number of loop sums (registers) required is the total number of binary places multiplied minus two after the "AND" operation at each intersection are done. So, \(2(n_b-1)\) loop sum registers are required. If the sum registers are staggered with the binary places aligned , then there is no need for shifting bits. \(n_b\) being the length (no. of bits) of the binary numbers being multiplied. The "AND" operation at each intersect is done concurrently, the "sum" operation within a loop is independent of other loops and must be done before the staggered loop sum operation. The summation within the loops are done concurrently followed by the sum across the staggered loops.
Another set of summing circuitry adds the loop sum in a staggered manner. aligned for each binary place. So, multiply can then be achieved with one "AND" and two "SUM" operations.
Good night...z z z
This is exactly as the decimal multiply done previously.
Luckily, this is not a jumping jack; shifting bits is slower than sum.
Total number of loop sums (registers) required is the total number of binary places multiplied minus two after the "AND" operation at each intersection are done. So, \(2(n_b-1)\) loop sum registers are required. If the sum registers are staggered with the binary places aligned , then there is no need for shifting bits. \(n_b\) being the length (no. of bits) of the binary numbers being multiplied. The "AND" operation at each intersect is done concurrently, the "sum" operation within a loop is independent of other loops and must be done before the staggered loop sum operation. The summation within the loops are done concurrently followed by the sum across the staggered loops.
Another set of summing circuitry adds the loop sum in a staggered manner. aligned for each binary place. So, multiply can then be achieved with one "AND" and two "SUM" operations.
Good night...z z z
Saturday, January 25, 2020
Electric Motor Wheel
An AC start sequence, that ramps up both frequency and current, starts the wheel spinning. Speed is controlled by varying the current in the induction coil.
Maybe...
Even if the coiled coil stator does produce a strong magnetic field, electrical induction at the wheel might not provide enough power to energize the electromagnetic coils on the spinning wheel and might not vary the speed enough to maneuver safely.
It is also possible,
In which case, the pump that drive the conductive fluid is spinning with the wheel and the power to the coil and pump is provided inductively (another set of induction coils).
Good day.
Maybe...
Even if the coiled coil stator does produce a strong magnetic field, electrical induction at the wheel might not provide enough power to energize the electromagnetic coils on the spinning wheel and might not vary the speed enough to maneuver safely.
It is also possible,
Good day.
Thursday, January 23, 2020
Super Torque Electric Motor
A coiled pipe with a negatively charged fluid pumped through it in a closed loop, generating a magnetic field.
The point is to have very high torque.
Good night
The point is to have very high torque.
Good night
Tuesday, January 21, 2020
Sunday, December 8, 2019
Lights in a jar
in remembrance of one
who advocates love
in an age of violence
when blood-lust was joy
Sparkles in a glass
in his eminence
by our hands abundance be
providence for us to give
love and care to share
Enlightenment in our hearts
darkness and shadows be gone
and forgiven
gentle and mercy to disarm
lawful be righteous and fair
Brightness aloft
our paths be guided
through trials and tribulations
resilience in failures
resolute in mis-course
Merry Christmas...
《Christmas 2019》
in remembrance of one
who advocates love
in an age of violence
when blood-lust was joy
Sparkles in a glass
in his eminence
by our hands abundance be
providence for us to give
love and care to share
Enlightenment in our hearts
darkness and shadows be gone
and forgiven
gentle and mercy to disarm
lawful be righteous and fair
Brightness aloft
our paths be guided
through trials and tribulations
resilience in failures
resolute in mis-course
Merry Christmas...
《Christmas 2019》
Pushing Sideways
Remember the pair of magnets that went sideways,
the force that pushes the magnets sideways must be due to the interactions of field lines perpendicular to the direction of attraction. One possibility is,
where at the ends of the magnets, the domains reversed and the field lines on one side run parallel to the end surface. The interactions of these field lines push the the magnets sideways. The diagram on the right shows a more definitive way to make such magnets. These are,
electromagnetic version of the same, where strong parallel field lines at the end of the them create a strong push side-way in a stater-rotor configuration.
Just thinking out loud.
the force that pushes the magnets sideways must be due to the interactions of field lines perpendicular to the direction of attraction. One possibility is,
where at the ends of the magnets, the domains reversed and the field lines on one side run parallel to the end surface. The interactions of these field lines push the the magnets sideways. The diagram on the right shows a more definitive way to make such magnets. These are,
electromagnetic version of the same, where strong parallel field lines at the end of the them create a strong push side-way in a stater-rotor configuration.
Just thinking out loud.
Saturday, December 7, 2019
Cosinusoidal Time
Consider the three time dimension spinning about the three space dimension,
The direction perpendicular to the \(t_c\) plane is the direction along that space dimension, \(x_c\). The expression for time along this axis is,
\(t_{\small{axis}}=-t_T sin \theta+t_g cos \theta=t(cos \theta-sin\theta)\)
\(t_{\small{axis}}=t\sqrt{2}cos(\theta+\cfrac{\pi}{4})\)
where we assume \(t_c=t_g=t_T=t\), that time is undifferentiated.
Is this formulation consistent with "the universe is a time particle" view; that a circular time wave passes through Earth at light speed, centered at the center of the universe?
Can the \(\sqrt{2}\) factor and the phase \(\small{\cfrac{\pi}{4}}\) be verified? What is the significance of these factors?
The direction perpendicular to the \(t_c\) plane is the direction along that space dimension, \(x_c\). The expression for time along this axis is,
\(t_{\small{axis}}=-t_T sin \theta+t_g cos \theta=t(cos \theta-sin\theta)\)
\(t_{\small{axis}}=t\sqrt{2}cos(\theta+\cfrac{\pi}{4})\)
where we assume \(t_c=t_g=t_T=t\), that time is undifferentiated.
Is this formulation consistent with "the universe is a time particle" view; that a circular time wave passes through Earth at light speed, centered at the center of the universe?
Can the \(\sqrt{2}\) factor and the phase \(\small{\cfrac{\pi}{4}}\) be verified? What is the significance of these factors?
If The Universe Is A Time Particle
If the universe is a time particle,
then a time wave around the center of the universe passes by Earth and imparts time onto the planet. A distorted particle in the path of such a wave travels through time. \
How do construct such a particle and be in such a particle to travel through time?
Since photons have been purported to be a wave with two orthogonal time component, spinning photons may just create a time field,
A distortion in this field can be introduced by displacing the light tube slightly,
Aligned in the direction of the time wave, it is then possible to move back and forth through time.
Yes, you sit inside the spinning tubes...
then a time wave around the center of the universe passes by Earth and imparts time onto the planet. A distorted particle in the path of such a wave travels through time. \
How do construct such a particle and be in such a particle to travel through time?
Since photons have been purported to be a wave with two orthogonal time component, spinning photons may just create a time field,
A distortion in this field can be introduced by displacing the light tube slightly,
Yes, you sit inside the spinning tubes...
Consistence About A Hartree
Hartree energy is defined as
\(E_H=2R_Hhc\)
From the post "Looking for Murder" dated 13 Oct 2018 it was proposed that,
\(R_H=\cfrac{1}{2\pi a_{\psi\,c}}\)
where \(R_H\) is the Rydberg constant
So,
\(E_H=2*\cfrac{hc}{2\pi a_{\psi\,c}}\)
but
\(f=\cfrac{c}{\lambda_{\psi\,c}}=\cfrac{c}{2\pi a_{\psi\,c}}\)
as
\(\lambda_{\psi\,c}=2\pi a_{\psi\,c}\)
we have,
\(E_H=2*hf_{\psi\,c}\) --- (*)
which only confirms that the prposed definition for \(R_H\) in the post "Looking for Murder" dated 13 Oct 2018 is dimensionally correct.
In the definition for Harttree Energy, this energy is approximately the electric potential energy of the hydrogen atom in its ground state and, by the virial theorem, approximately twice its ionization energy; the relationships are not exact because of the finite mass of the nucleus of the hydrogen atom and relativistic corrections.
\(a_{\psi}=14.77\,nm\) is a particle defined by \(\psi\) in circular motion; Hartree Energy sees an electron in orbit around a hydrogen nucleus.
This contention is not new and has been resolved by thinking that the electron is a wave going in orbit.
The posts presented here however, takes the view that the electron is made up of a \(\psi\) wave warped around a sphere. A \(\psi\) wave in circular motion. Enegry changes of this wave result in the spectral lines. The electron need not be in orbit around the hydrogen nucleus.
The size of a hydrogen atom is in the range of \(\times 10^{-15}\) meters, \(fm\),
but a consistent \(a_{\psi\,c}\), according to (*) is in the range of tenth of \(\times 10^{-9}\).
An electron at \(a_{\psi\,c}\) from the hydrogen nucleus cannot be at the ground state.
A particle, however, can have a force field around it up to \(\times10^{-9}\) meters.
Good night...
\(E_H=2R_Hhc\)
From the post "Looking for Murder" dated 13 Oct 2018 it was proposed that,
\(R_H=\cfrac{1}{2\pi a_{\psi\,c}}\)
where \(R_H\) is the Rydberg constant
So,
\(E_H=2*\cfrac{hc}{2\pi a_{\psi\,c}}\)
but
\(f=\cfrac{c}{\lambda_{\psi\,c}}=\cfrac{c}{2\pi a_{\psi\,c}}\)
as
\(\lambda_{\psi\,c}=2\pi a_{\psi\,c}\)
we have,
\(E_H=2*hf_{\psi\,c}\) --- (*)
which only confirms that the prposed definition for \(R_H\) in the post "Looking for Murder" dated 13 Oct 2018 is dimensionally correct.
In the definition for Harttree Energy, this energy is approximately the electric potential energy of the hydrogen atom in its ground state and, by the virial theorem, approximately twice its ionization energy; the relationships are not exact because of the finite mass of the nucleus of the hydrogen atom and relativistic corrections.
\(a_{\psi}=14.77\,nm\) is a particle defined by \(\psi\) in circular motion; Hartree Energy sees an electron in orbit around a hydrogen nucleus.
This contention is not new and has been resolved by thinking that the electron is a wave going in orbit.
The posts presented here however, takes the view that the electron is made up of a \(\psi\) wave warped around a sphere. A \(\psi\) wave in circular motion. Enegry changes of this wave result in the spectral lines. The electron need not be in orbit around the hydrogen nucleus.
The size of a hydrogen atom is in the range of \(\times 10^{-15}\) meters, \(fm\),
but a consistent \(a_{\psi\,c}\), according to (*) is in the range of tenth of \(\times 10^{-9}\).
An electron at \(a_{\psi\,c}\) from the hydrogen nucleus cannot be at the ground state.
A particle, however, can have a force field around it up to \(\times10^{-9}\) meters.
Good night...
For Completeness Sake, Freaking Out
From the post "What If The Particles Are Photons?" dated 12 Dec 2017,
\(f=\cfrac{c}{\lambda}=\cfrac{8^3}{18}\pi^2=280.74\,Hz\)
we can have,
\(f=3*280.74\,Hz=842.21\,Hz\)
But,
what is \(w\)? to realize such a 3D confinement portal. It is hoped that with
\(w\gt842.21\,Hz\) and
\(w\) being prime, we may have a prime dialed portal to walk into and walk out.
Just science friction.
\(f=\cfrac{c}{\lambda}=\cfrac{8^3}{18}\pi^2=280.74\,Hz\)
we can have,
\(f=3*280.74\,Hz=842.21\,Hz\)
But,
what is \(w\)? to realize such a 3D confinement portal. It is hoped that with
\(w\gt842.21\,Hz\) and
\(w\) being prime, we may have a prime dialed portal to walk into and walk out.
Just science friction.
Don't Freak Out
Yet another mistake...in the post "Freaking Out Entanglement" dated 14 Dec 2017,
\(P=\cfrac{8^3}{6}{\pi^2}∗f^2∗m_ac^2=1∗\cfrac{4}{3}\pi∗f^3∗m_ac^2\)
should be
\(P=\cfrac{8^3}{6}{\pi^2}∗f^2∗m_ac^2=1∗\cfrac{3}{4\pi}∗f^3∗m_ac^2\)
\(f=\cfrac{4*8^3}{18}\pi^3=3527.83 Hz\) Very dangerous! Do not look into the light, at all. No exposure in anyway.
\(P=\cfrac{8^3}{6}{\pi^2}∗f^2∗m_ac^2=1∗\cfrac{4}{3}\pi∗f^3∗m_ac^2\)
should be
\(P=\cfrac{8^3}{6}{\pi^2}∗f^2∗m_ac^2=1∗\cfrac{3}{4\pi}∗f^3∗m_ac^2\)
\(f=\cfrac{4*8^3}{18}\pi^3=3527.83 Hz\) Very dangerous! Do not look into the light, at all. No exposure in anyway.
and
\(f=64*\pi=201.06\,Hz\) is wrong!
Sorry...
To Clear Things Up
I have made a mistake in the post "I Don't Know..." dated 12 Dec 2017, in the expression
\(P=\cfrac{8^3}{18}{\pi^2}∗f^2∗m_ac^2=1∗\cfrac{4}{3}\pi∗f^3∗m_ac^2\)
It should be
\(P=\cfrac{8^3}{18}{\pi^2}∗f^2∗m_ac^2=1∗\cfrac{3}{4\pi}∗f^3∗m_ac^2\)
where the \(RHS\) is divided by a spherical volume to obtain energy per unit volume. The expression leads to,
\(f=\cfrac{4*8^3}{3*18}\pi^3=1175.94 Hz\)
The previous result,
\(f=\cfrac{8^3}{24}\pi=67.02\,Hz\)
is not valid.
Sorry...
\(P=\cfrac{8^3}{18}{\pi^2}∗f^2∗m_ac^2=1∗\cfrac{4}{3}\pi∗f^3∗m_ac^2\)
It should be
\(P=\cfrac{8^3}{18}{\pi^2}∗f^2∗m_ac^2=1∗\cfrac{3}{4\pi}∗f^3∗m_ac^2\)
where the \(RHS\) is divided by a spherical volume to obtain energy per unit volume. The expression leads to,
\(f=\cfrac{4*8^3}{3*18}\pi^3=1175.94 Hz\)
The previous result,
\(f=\cfrac{8^3}{24}\pi=67.02\,Hz\)
is not valid.
Sorry...
Saturday, September 7, 2019
Torturing Fish
There is more oxygen in the air than in water, so a fish out of water is hyperventilating. It is not grasping for air.
A drop of oil on the outer gill, leaving the rest of the gills not coated, may prevent the fish from dying too soon. Other than oil, other options such as starch of liquid consistency, agar-agar with pineapple juice (that prevents the agar-agar from setting) can be experimented with. The point is to cover the gills and prevent hyperventilation.
Good night...z.z.z
A drop of oil on the outer gill, leaving the rest of the gills not coated, may prevent the fish from dying too soon. Other than oil, other options such as starch of liquid consistency, agar-agar with pineapple juice (that prevents the agar-agar from setting) can be experimented with. The point is to cover the gills and prevent hyperventilation.
Good night...z.z.z
The Old Model
The Old Model is to consider a chemical bond as a particle whose diameter is the bond length. As such, all resonance associated with a particle is applicable to the chemical bond. For example,
\(f_{res}=0.061\cfrac{c}{a_{\psi}}\)
\(a_{\psi}=\cfrac{1}{2}BL\)
\(f_{res}=0.122\cfrac{c}{BL}\)
The radius of such a particle is half the bond length, \(BL\).
\(f_{res}=0.061\cfrac{c}{a_{\psi}}\)
\(a_{\psi}=\cfrac{1}{2}BL\)
\(f_{res}=0.122\cfrac{c}{BL}\)
The radius of such a particle is half the bond length, \(BL\).
Wednesday, March 20, 2019
Ammonia Is Important
This post was missing; a cold stream of hydrogen gas mixed with a warm stream of nitrogen gas to produce ammonia without high pressure and temperature.
It is not a mix of cold nitrogen and hot hydrogen because I remember a jet of hydrogen gas from a high pressure cylinder smells like ammonia and that ammonia is found in dark underground where warm air mix in with the cold and damp.
This post came after the postulate that there is another class of chemistry involving temperature particles, where a temperature difference provides for the disparity in temperature charge, analogous the electric charge that fills oxidation states in normal chemistry.
I am not back; data is very expensive.
It is not a mix of cold nitrogen and hot hydrogen because I remember a jet of hydrogen gas from a high pressure cylinder smells like ammonia and that ammonia is found in dark underground where warm air mix in with the cold and damp.
This post came after the postulate that there is another class of chemistry involving temperature particles, where a temperature difference provides for the disparity in temperature charge, analogous the electric charge that fills oxidation states in normal chemistry.
I am not back; data is very expensive.
Thursday, January 10, 2019
Where It Isn't
One way to proof the validity of \(f_{osc}\) and the associated \(I_{osc}=q_e*f_{osc}\) where \(q_e\) is the electron charge, is to pass such a current, \(I_{osc}\), through a metal whose photoelectric threshold frequency cannot be obtained (usually where the expected threshold frequency is at the edge of the producible light spectrum) during the experiment to obtain the threshold frequency.
In another words, repeat the experiment to obtain \(f_{threshold}\) with \(I_{osc}\) following through the metal.
To find where there was none...
In another words, repeat the experiment to obtain \(f_{threshold}\) with \(I_{osc}\) following through the metal.
To find where there was none...
Wednesday, January 9, 2019
I Found The Rabbit Hole
This is being thick skin about why \(f_{osc}\) is not the photoelectric emission threshold frequency.
This line of best fit has gradient\(\rightarrow\infty\) as \(x\rightarrow\infty\). For any such line fitted closer to the origin, it has gradient \(\lt\infty\). "Threshold", the x-intercept of this line is not unique.
This is a line to fit V-I characteristics of a gas discharge tube at the onset of glow discharge,
where \(x=log(I)\). The drop in voltage here is attributed to negative charges created.
This should not be confused with,
\(K_{max}=hf-\Phi\)
where \(K_{max}\) is the maximum kinetic energy of ejected electrons and \(\Phi=hf_o\) the Work Function defined by \(f_o\), the threshold frequency. This relation answers the question: "What happens to the excess energy of the photon beyond \(\Phi\) after impact?"
Using sodium, \(Na\)
\(f_o=4.39*10^{14}\,Hz\)
If we reverse and find \(a_{\psi}\) using
\(f_{osc}=c\sqrt{\cfrac{2\pi}{a_{\psi}}}\) --- (*)
with a change in notation,
\(f_{hole}=c\sqrt{\cfrac{2\pi}{a_{\psi\,hole}}}\)
\(a_{\psi\,hole}=2\pi\left(\cfrac{c}{f_{hole}}\right)^2=2.93\text{e-}12\,m\)
What is this small hole?
Could it be that \(f_{osc}\) of sodium, opens up this small hole and subsequent photons that falls into it, is split into two parts,
\(K_{max}=hf-\Phi\)
\(\Phi=hf_{hole}\), \(f\) is the frequency of the impacting photons and \(K_{max}\) is the maximum kinetic energy of the ejected particles. \(f_{osc}\) of sodium is given by,
\(f_{osc}=c\sqrt{\cfrac{2\pi}{a_{\psi\,Na}}}\)
where \(a_{\psi\,Na}\) is the size of sodium \(\psi\) cloud.
\(f_{osc}\) opens up a hole denoted by \(a_{\psi\,hole}\), and all photons at greater size than \(a_{\psi\,hole}\) (lower frequency than \(f_{hole}\), as indicated by (*)) are rejected by the hole. If this is the role of \(f_{osc}\), then using a narrow bandwidth of photons at \(f_{osc}\) and illuminating the metal with photons at bigger size than \(a_{hole}\) will cause the metal to appear very bright and without the emission of charged particles. All illuminating photons is rejected by the hole opened by \(f_{osc}\).
Photons of size smaller, \(a_{\psi}\lt a_{\psi\,hole}\) falls into the hole. When do such photons return after falling into the hole? What dictates the size of the hole? Hole of different sizes could explain the seemingly different processes that occurs simultaneously during photoelectric emission where two \(K_{max}\) values were noted. The post related to this is "More Fodo Effects" dated 04 Jun 2014; two related diagrams are shown below,
Impurities could explain the two \(K_{max}s\).
\(f_{hole}\) is the threshold frequency. Given \(f_{\psi}\), \(a_{\psi}\) can be derived given,
\(2\pi a_{\psi}=n\lambda=n\cfrac{c}{f_{\psi}}\)
\(f_{\psi}=\cfrac{c}{2\pi a_{\psi}}\), with \(n=1\)
but an impacting photon interact through,
\(f_{\psi}=c\sqrt{\cfrac{2\pi}{a_{\psi}}}\)
when \(f_{\psi}\gt f_{hole}\), \(a_{\psi}\lt a_{\psi\,hole}\) and the photon goes through the hole, and its energy is split via,
\(K_{max}=hf-\Phi\)
\(\Phi=hf_{hole}\) and \(K_{max}\) is the maximum kinetic energy of a emitted particle.
\(f_{osc}\) that triggers \(f_{hole}\) is lower than \(f_{hole}\). \(f_{hole}\) alone does not cause photoelectric emission. \(f_{osc}\), a frequency below the threshold, has first to create the hole, via a mode of oscillation with resonance at,
\(f_{osc}=c\sqrt{\cfrac{2\pi}{a_{\psi}}}\)
where \(a_{\psi}\) is the size of the \(\psi\) ball.
This hole is in effect, a region of negative energy that minus off energy of subsequent impacting photons of higher frequencies. Photons of lower frequencies are too big to fit into the hole. And only the resonance frequency, \(f_{osc}\) opens the hole in the metal.
Besides being convoluted, this explanation does not hold \(a_{\psi\,hole}\) at all, apart from the exertion that \(f_{osc}\) caused it. It however, allows for many size holes that can account for more than one \(K_{max}\) and allows \(f_{osc}\) to be different from the threshold frequency. But charges are still created within the metal at \(f_{osc}\) and, higher frequency photons interacting with the holes created can be outside the metal, ie emitted, when they return from the time dimension.
How does \(f_{osc}\) create charges? \(f_{osc}\) set the \(\psi\) cloud of the atom into resonance and the atom loses its orbiting valence electrons. And, how a photon of higher energy \(f_{\psi}\gt f_{hole}\) ejects a particle of kinetic energy \(K_{max}\) after filling in the hole? The hole requires \(E=hf_{hole}\), what remains of the impacting photons with higher energy after making good for the hole is like a torus photon (posts "What Donuts? Dipoles?" and "Torus Photons" dated 29 Dec 2017).
\(K_{max}=hf_{\psi}-hf_{hole}\)
When the torus photon collapses however, the resulting particle may not have a full unit charge. It may be a partial charge of size smaller than \(a_{\psi\,c}\).
Is \(f_{osc}\) valid?
Note: The previous version of this post has mistaken \(f_{osc}\gt f_{o}\) or \(f_{hole}\) that was wrong.
This line of best fit has gradient\(\rightarrow\infty\) as \(x\rightarrow\infty\). For any such line fitted closer to the origin, it has gradient \(\lt\infty\). "Threshold", the x-intercept of this line is not unique.
This is a line to fit V-I characteristics of a gas discharge tube at the onset of glow discharge,
where \(x=log(I)\). The drop in voltage here is attributed to negative charges created.
This should not be confused with,
\(K_{max}=hf-\Phi\)
where \(K_{max}\) is the maximum kinetic energy of ejected electrons and \(\Phi=hf_o\) the Work Function defined by \(f_o\), the threshold frequency. This relation answers the question: "What happens to the excess energy of the photon beyond \(\Phi\) after impact?"
Using sodium, \(Na\)
\(f_o=4.39*10^{14}\,Hz\)
If we reverse and find \(a_{\psi}\) using
\(f_{osc}=c\sqrt{\cfrac{2\pi}{a_{\psi}}}\) --- (*)
with a change in notation,
\(f_{hole}=c\sqrt{\cfrac{2\pi}{a_{\psi\,hole}}}\)
\(a_{\psi\,hole}=2\pi\left(\cfrac{c}{f_{hole}}\right)^2=2.93\text{e-}12\,m\)
What is this small hole?
Could it be that \(f_{osc}\) of sodium, opens up this small hole and subsequent photons that falls into it, is split into two parts,
\(K_{max}=hf-\Phi\)
\(\Phi=hf_{hole}\), \(f\) is the frequency of the impacting photons and \(K_{max}\) is the maximum kinetic energy of the ejected particles. \(f_{osc}\) of sodium is given by,
\(f_{osc}=c\sqrt{\cfrac{2\pi}{a_{\psi\,Na}}}\)
where \(a_{\psi\,Na}\) is the size of sodium \(\psi\) cloud.
\(f_{osc}\) opens up a hole denoted by \(a_{\psi\,hole}\), and all photons at greater size than \(a_{\psi\,hole}\) (lower frequency than \(f_{hole}\), as indicated by (*)) are rejected by the hole. If this is the role of \(f_{osc}\), then using a narrow bandwidth of photons at \(f_{osc}\) and illuminating the metal with photons at bigger size than \(a_{hole}\) will cause the metal to appear very bright and without the emission of charged particles. All illuminating photons is rejected by the hole opened by \(f_{osc}\).
Photons of size smaller, \(a_{\psi}\lt a_{\psi\,hole}\) falls into the hole. When do such photons return after falling into the hole? What dictates the size of the hole? Hole of different sizes could explain the seemingly different processes that occurs simultaneously during photoelectric emission where two \(K_{max}\) values were noted. The post related to this is "More Fodo Effects" dated 04 Jun 2014; two related diagrams are shown below,
Impurities could explain the two \(K_{max}s\).
\(f_{hole}\) is the threshold frequency. Given \(f_{\psi}\), \(a_{\psi}\) can be derived given,
\(2\pi a_{\psi}=n\lambda=n\cfrac{c}{f_{\psi}}\)
\(f_{\psi}=\cfrac{c}{2\pi a_{\psi}}\), with \(n=1\)
but an impacting photon interact through,
\(f_{\psi}=c\sqrt{\cfrac{2\pi}{a_{\psi}}}\)
when \(f_{\psi}\gt f_{hole}\), \(a_{\psi}\lt a_{\psi\,hole}\) and the photon goes through the hole, and its energy is split via,
\(K_{max}=hf-\Phi\)
\(\Phi=hf_{hole}\) and \(K_{max}\) is the maximum kinetic energy of a emitted particle.
\(f_{osc}\) that triggers \(f_{hole}\) is lower than \(f_{hole}\). \(f_{hole}\) alone does not cause photoelectric emission. \(f_{osc}\), a frequency below the threshold, has first to create the hole, via a mode of oscillation with resonance at,
\(f_{osc}=c\sqrt{\cfrac{2\pi}{a_{\psi}}}\)
where \(a_{\psi}\) is the size of the \(\psi\) ball.
This hole is in effect, a region of negative energy that minus off energy of subsequent impacting photons of higher frequencies. Photons of lower frequencies are too big to fit into the hole. And only the resonance frequency, \(f_{osc}\) opens the hole in the metal.
Besides being convoluted, this explanation does not hold \(a_{\psi\,hole}\) at all, apart from the exertion that \(f_{osc}\) caused it. It however, allows for many size holes that can account for more than one \(K_{max}\) and allows \(f_{osc}\) to be different from the threshold frequency. But charges are still created within the metal at \(f_{osc}\) and, higher frequency photons interacting with the holes created can be outside the metal, ie emitted, when they return from the time dimension.
How does \(f_{osc}\) create charges? \(f_{osc}\) set the \(\psi\) cloud of the atom into resonance and the atom loses its orbiting valence electrons. And, how a photon of higher energy \(f_{\psi}\gt f_{hole}\) ejects a particle of kinetic energy \(K_{max}\) after filling in the hole? The hole requires \(E=hf_{hole}\), what remains of the impacting photons with higher energy after making good for the hole is like a torus photon (posts "What Donuts? Dipoles?" and "Torus Photons" dated 29 Dec 2017).
\(K_{max}=hf_{\psi}-hf_{hole}\)
When the torus photon collapses however, the resulting particle may not have a full unit charge. It may be a partial charge of size smaller than \(a_{\psi\,c}\).
Is \(f_{osc}\) valid?
Note: The previous version of this post has mistaken \(f_{osc}\gt f_{o}\) or \(f_{hole}\) that was wrong.
Tuesday, January 8, 2019
Pulling Crystals
This was what I thought of pulling silicon crystal,
and the artifacts that it creates. This is what I thought that would reduce such ringing artifacts,
\(\theta\) for diamond cubic crystals will be,
\(OA=OC=\cfrac{3}{4}\sqrt{\cfrac{2}{3}}a\)
\(OH=\cfrac{1}{4}\sqrt{\cfrac{2}{3}}a\)
\(\theta=arcsin(\cfrac{OH}{OC})=arcsin(\cfrac{1}{3})=19.47^o\).
where \(C\) is at the first layer and is bonded to the next layer of silicon is at \(O\). The next pull does not form up the bond along \(OA\), but it is at \(19.47^o\) from \(O\). Bonds similar to \(CO\) form up else where in the crystal. After four steps, because \(OH=\cfrac{1}{4}AH\), the atom needed at \(A\) falls into place. At each step, a sheet of atoms is shifted into place.
Good night...
and the artifacts that it creates. This is what I thought that would reduce such ringing artifacts,
\(\theta\) for diamond cubic crystals will be,
\(OA=OC=\cfrac{3}{4}\sqrt{\cfrac{2}{3}}a\)
\(OH=\cfrac{1}{4}\sqrt{\cfrac{2}{3}}a\)
\(\theta=arcsin(\cfrac{OH}{OC})=arcsin(\cfrac{1}{3})=19.47^o\).
where \(C\) is at the first layer and is bonded to the next layer of silicon is at \(O\). The next pull does not form up the bond along \(OA\), but it is at \(19.47^o\) from \(O\). Bonds similar to \(CO\) form up else where in the crystal. After four steps, because \(OH=\cfrac{1}{4}AH\), the atom needed at \(A\) falls into place. At each step, a sheet of atoms is shifted into place.
Good night...
Townsend Discharge In Solids
Cont'd from the post "Hollow Metal" dated 29 Dec 2018, if the matter is a gas, \(I_{osc}=q_e*f_{osc}\) might be Townsend discharge, where \(q_e=1.602176565\text{e-19}\,C\)
A table of \(I_{osc}\) for covalent bond is given below.
Apart from the fact that \(I_{osc}\approx10^{-6}\,\text{to}\,10^{-5}\), there is no reason to believe that \(I_{osc}\) triggers Townsend discharge.
However, if \(I_{osc}\) does trigger a discharge, then the negative charges produced during resonance will reduce the measured voltage and increase the current. The changes in current and voltage are continued only if the resonance is sustained. This means, the current remains at \(I_{osc}\). Superimposed on this is the effect of created charges that reduces the voltage and increases the current. The applied voltage is also constant. Townsend discharge then does not occur unless \(I_{osc}\) is achieved first with a specific applied voltage (\(V_{osc}\)) and maintained at this specific voltage. As long as there are free charges inside the tube, the tube is conductive. If this is the case, a discharge tube when subjected to a higher voltage that produces a higher current, \(I\gt I_{osc}\), will not glow or arc as there are no free charges in the tube. This would refute the ionization-avalanche mechanism as the explanation for discharge because this mechanism should also occur at higher voltage. Does \(V_{osc}\) exist for sustained discharge? And that all discharge must pass through \(V_{osc}\)?
Does this happen in a metal like \(Cu\) where a current \(I_{osc}=1.025\text{e-05}\,A\) creates more charge carriers?
Maybe...
Note: no data means no data but its does not mean no information, not including them will be wrong.
A table of \(I_{osc}\) for covalent bond is given below.
| atomic no. | symbol | name | Covalent (single bond) pm | f_osc (10^14)Hz | _hf eV | q_e*f_osc A |
| 1 | H | hydrogen | 38 | 1.2190 | 0.504 | 1.953E-05 |
| 2 | He | helium | 32 | 1.3284 | 0.549 | 2.128E-05 |
| 3 | Li | lithium | 134 | 0.6492 | 0.268 | 1.040E-05 |
| 4 | Be | beryllium | 90 | 0.7921 | 0.328 | 1.269E-05 |
| 5 | B | boron | 82 | 0.8299 | 0.343 | 1.330E-05 |
| 6 | C | carbon | 77 | 0.8564 | 0.354 | 1.372E-05 |
| 7 | N | nitrogen | 75 | 0.8677 | 0.359 | 1.390E-05 |
| 8 | O | oxygen | 73 | 0.8795 | 0.364 | 1.409E-05 |
| 9 | F | fluorine | 71 | 0.8918 | 0.369 | 1.429E-05 |
| 10 | Ne | neon | 69 | 0.9047 | 0.374 | 1.449E-05 |
| 11 | Na | sodium | 154 | 0.6056 | 0.250 | 9.702E-06 |
| 12 | Mg | magnesium | 130 | 0.6591 | 0.273 | 1.056E-05 |
| 13 | Al | aluminium | 118 | 0.6918 | 0.286 | 1.108E-05 |
| 14 | Si | silicon | 111 | 0.7133 | 0.295 | 1.143E-05 |
| 15 | P | phosphorus | 106 | 0.7299 | 0.302 | 1.169E-05 |
| 16 | S | sulfur | 102 | 0.7441 | 0.308 | 1.192E-05 |
| 17 | Cl | chlorine | 99 | 0.7553 | 0.312 | 1.210E-05 |
| 18 | Ar | argon | 97 | 0.7630 | 0.316 | 1.222E-05 |
| 19 | K | potassium | 196 | 0.5368 | 0.222 | 8.600E-06 |
| 20 | Ca | calcium | 174 | 0.5697 | 0.236 | 9.127E-06 |
| 21 | Sc | scandium | 144 | 0.6262 | 0.259 | 1.003E-05 |
| 22 | Ti | titanium | 136 | 0.6444 | 0.266 | 1.032E-05 |
| 23 | V | vanadium | 125 | 0.6721 | 0.278 | 1.077E-05 |
| 24 | Cr | chromium | 127 | 0.6668 | 0.276 | 1.068E-05 |
| 25 | Mn | manganese | 139 | 0.6374 | 0.264 | 1.021E-05 |
| 26 | Fe | iron | 125 | 0.6721 | 0.278 | 1.077E-05 |
| 27 | Co | cobalt | 126 | 0.6695 | 0.277 | 1.073E-05 |
| 28 | Ni | nickel | 121 | 0.6832 | 0.283 | 1.095E-05 |
| 29 | Cu | copper | 138 | 0.6397 | 0.265 | 1.025E-05 |
| 30 | Zn | zinc | 131 | 0.6566 | 0.272 | 1.052E-05 |
| 31 | Ga | gallium | 126 | 0.6695 | 0.277 | 1.073E-05 |
| 32 | Ge | germanium | 122 | 0.6803 | 0.281 | 1.090E-05 |
| 33 | As | arsenic | 119 | 0.6889 | 0.285 | 1.104E-05 |
| 34 | Se | selenium | 116 | 0.6977 | 0.289 | 1.118E-05 |
| 35 | Br | bromine | 114 | 0.7038 | 0.291 | 1.128E-05 |
| 36 | Kr | krypton | 110 | 0.7165 | 0.296 | 1.148E-05 |
| 37 | Rb | rubidium | 211 | 0.5173 | 0.214 | 8.289E-06 |
| 38 | Sr | strontium | 192 | 0.5423 | 0.224 | 8.689E-06 |
| 39 | Y | yttrium | 162 | 0.5904 | 0.244 | 9.459E-06 |
| 40 | Zr | zirconium | 148 | 0.6177 | 0.255 | 9.897E-06 |
| 41 | Nb | niobium | 137 | 0.6420 | 0.266 | 1.029E-05 |
| 42 | Mo | molybdenum | 145 | 0.6241 | 0.258 | 9.999E-06 |
| 43 | Tc | technetium | 156 | 0.6017 | 0.249 | 9.640E-06 |
| 44 | Ru | ruthenium | 126 | 0.6695 | 0.277 | 1.073E-05 |
| 45 | Rh | rhodium | 135 | 0.6468 | 0.267 | 1.036E-05 |
| 46 | Pd | palladium | 131 | 0.6566 | 0.272 | 1.052E-05 |
| 47 | Ag | silver | 153 | 0.6075 | 0.251 | 9.734E-06 |
| 48 | Cd | cadmium | 148 | 0.6177 | 0.255 | 9.897E-06 |
| 49 | In | indium | 144 | 0.6262 | 0.259 | 1.003E-05 |
| 50 | Sn | tin | 141 | 0.6329 | 0.262 | 1.014E-05 |
| 51 | Sb | antimony | 138 | 0.6397 | 0.265 | 1.025E-05 |
| 52 | Te | tellurium | 135 | 0.6468 | 0.267 | 1.036E-05 |
| 53 | I | iodine | 133 | 0.6516 | 0.269 | 1.044E-05 |
| 54 | Xe | xenon | 130 | 0.6591 | 0.273 | 1.056E-05 |
| 55 | Cs | caesium | 225 | 0.5010 | 0.207 | 8.027E-06 |
| 56 | Ba | barium | 198 | 0.5340 | 0.221 | 8.556E-06 |
| 57 | La | lanthanum | 169 | 0.5781 | 0.239 | 9.261E-06 |
| 58 | Ce | cerium | no data | no data | no data | no data |
| 59 | Pr | praseodymium | no data | no data | no data | no data |
| 60 | Nd | neodymium | no data | no data | no data | no data |
| 61 | Pm | promethium | no data | no data | no data | no data |
| 62 | Sm | samarium | no data | no data | no data | no data |
| 63 | Eu | europium | no data | no data | no data | no data |
| 64 | Gd | gadolinium | no data | no data | no data | no data |
| 65 | Tb | terbium | no data | no data | no data | no data |
| 66 | Dy | dysprosium | no data | no data | no data | no data |
| 67 | Ho | holmium | no data | no data | no data | no data |
| 68 | Er | erbium | no data | no data | no data | no data |
| 69 | Tm | thulium | no data | no data | no data | no data |
| 70 | Yb | ytterbium | no data | no data | no data | no data |
| 71 | Lu | lutetium | 160 | 0.5941 | 0.246 | 9.518E-06 |
| 72 | Hf | hafnium | 150 | 0.6136 | 0.254 | 9.830E-06 |
| 73 | Ta | tantalum | 138 | 0.6397 | 0.265 | 1.025E-05 |
| 74 | W | tungsten | 146 | 0.6219 | 0.257 | 9.964E-06 |
| 75 | Re | rhenium | 159 | 0.5960 | 0.246 | 9.548E-06 |
| 76 | Os | osmium | 128 | 0.6642 | 0.275 | 1.064E-05 |
| 77 | Ir | iridium | 137 | 0.6420 | 0.266 | 1.029E-05 |
| 78 | Pt | platinum | 128 | 0.6642 | 0.275 | 1.064E-05 |
| 79 | Au | gold | 144 | 0.6262 | 0.259 | 1.003E-05 |
| 80 | Hg | mercury | 149 | 0.6156 | 0.255 | 9.863E-06 |
| 81 | Tl | thallium | 148 | 0.6177 | 0.255 | 9.897E-06 |
| 82 | Pb | lead | 147 | 0.6198 | 0.256 | 9.930E-06 |
| 83 | Bi | bismuth | 146 | 0.6219 | 0.257 | 9.964E-06 |
| 84 | Po | polonium | no data | no data | no data | no data |
| 85 | At | astatine | no data | no data | no data | no data |
| 86 | Rn | radon | 145 | 0.6241 | 0.258 | 9.999E-06 |
| 87 | Fr | francium | no data | no data | no data | no data |
| 88 | Ra | radium | no data | no data | no data | no data |
| 89 | Ac | actinium | no data | no data | no data | no data |
| 90 | Th | thorium | no data | no data | no data | no data |
| 91 | Pa | protactinium | no data | no data | no data | no data |
| 92 | U | uranium | no data | no data | no data | no data |
| 93 | Np | neptunium | no data | no data | no data | no data |
| 94 | Pu | plutonium | no data | no data | no data | no data |
| 95 | Am | americium | no data | no data | no data | no data |
| 96 | Cm | curium | no data | no data | no data | no data |
| 97 | Bk | berkelium | no data | no data | no data | no data |
| 98 | Cf | californium | no data | no data | no data | no data |
| 99 | Es | einsteinium | no data | no data | no data | no data |
| 100 | Fm | fermium | no data | no data | no data | no data |
| 101 | Md | mendelevium | no data | no data | no data | no data |
| 102 | No | nobelium | no data | no data | no data | no data |
| 103 | Lr | lawrencium | no data | no data | no data | no data |
| 104 | Rf | rutherfordium | no data | no data | no data | no data |
| 105 | Db | dubnium | no data | no data | no data | no data |
| 106 | Sg | seaborgium | no data | no data | no data | no data |
| 107 | Bh | bohrium | no data | no data | no data | no data |
| 108 | Hs | hassium | no data | no data | no data | no data |
| 109 | Mt | meitnerium | no data | no data | no data | no data |
| 110 | Ds | darmstadtium | no data | no data | no data | no data |
| 111 | Rg | roentgenium | no data | no data | no data | no data |
| 112 | Cn | copernicium | no data | no data | no data | no data |
| 113 | Nh | nihonium | no data | no data | no data | no data |
| 114 | Fl | flerovium | no data | no data | no data | no data |
| 115 | Mc | moscovium | no data | no data | no data | no data |
| 116 | Lv | livermorium | no data | no data | no data | no data |
| 117 | Ts | tennessine | no data | no data | no data | no data |
| 118 | Og | oganesson | no data | no data | no data | no data |
Apart from the fact that \(I_{osc}\approx10^{-6}\,\text{to}\,10^{-5}\), there is no reason to believe that \(I_{osc}\) triggers Townsend discharge.
However, if \(I_{osc}\) does trigger a discharge, then the negative charges produced during resonance will reduce the measured voltage and increase the current. The changes in current and voltage are continued only if the resonance is sustained. This means, the current remains at \(I_{osc}\). Superimposed on this is the effect of created charges that reduces the voltage and increases the current. The applied voltage is also constant. Townsend discharge then does not occur unless \(I_{osc}\) is achieved first with a specific applied voltage (\(V_{osc}\)) and maintained at this specific voltage. As long as there are free charges inside the tube, the tube is conductive. If this is the case, a discharge tube when subjected to a higher voltage that produces a higher current, \(I\gt I_{osc}\), will not glow or arc as there are no free charges in the tube. This would refute the ionization-avalanche mechanism as the explanation for discharge because this mechanism should also occur at higher voltage. Does \(V_{osc}\) exist for sustained discharge? And that all discharge must pass through \(V_{osc}\)?
Does this happen in a metal like \(Cu\) where a current \(I_{osc}=1.025\text{e-05}\,A\) creates more charge carriers?
Maybe...
Note: no data means no data but its does not mean no information, not including them will be wrong.