From the post "Hydrogen, And Everyone Has His Spins" dated 10 Jun 2014, the calculated distance between the two positive nuclei is,
\(r_{pp}=\text{3.20e-18}\,\,m\)
If the formula,
\(f_{res}=0.122\cfrac{c}{BL}\)
also applies with \(BL=r_{pp}\) then,
\(f_{res}=0.122\cfrac{c}{3.20*10^{-18}}=1.142958746125*10^{25}\)
\(\cfrac{f_{res}}{10^{22}}=\cfrac{1.1429587*10^{25}}{10^{22}}=1142.959\,\,Hz\)
Given that a frequency at integer divisor lower than \(f_{res}\) will also produce resonance, then 1142.959 Hz will cause all the hydrogen molecules to line up and freeze into a solid.
Note:
If more figures are allowed for \(r_{pp}=3.20382*10^{-18}\) then,
\(f_{res}=1.141596*10^{25}\) or \(\cfrac{f_{res}}{10^{22}}=1141.596\,\,Hz\)
