The Familiar Squeeze

I must have this before,

If  the velocity of the particle is $c$ then,

$v=c.sin(\theta)$ 

And the distortion to the particle and/or its path, due to the force acting in the direction opposite to $v$ is  zero when $\theta=0$ because $v=0$ according to the above.  The force that distorts the particle is along in the plane of the particle's circular motion.  As is the case when $\theta=90^o$.

The mid point between these two equivalent extremes is at $\theta=45^o$.

Is this the same squeeze as before?  Maybe...