where the particle spins is not in the plane perpendicular to the direction of travel along \(v\). In this case, the direction of \(F\) given by \(\omega\times v\) is in the plane of the spin, as \(\omega\) is perpendicular to this plane,
\(F\) is perpendicular to \(v\) and does not retard \(v\) but it is in the direction opposite to the centripetal force that keeps the particle in spin, on the side indicated by the right hand rule (\(\omega\times v\)). The particle move further from the center on this side,
and on the opposite side moves closer to the center, assuming that \(v\) is constant. The particle bulge on the side to which it turned. The opposite side, contracted.
When \(\theta=90^o\), \(F=0\) because \(cos(\theta)=0\) and if \(theta\) is indicative of the deformation on the particle,
in this direction of spin, the particle has maximum distortion at \(\theta=90^o\), \(F=0\).
This might be the interpretation for \(\theta\) in the post "A Pump!" and "Polarization And Invisibility" both dated 25 Jul 2015, etc.
Energy is stored in the deformation and this energy is released when the deformation on the particle relents.
This however is a non-quantized release of energy...unless \(\theta\) is restricted in some way to discrete values.
In the case of light released over a range of energy values; light photons within a ranged bandwidth; multicolored.
