Yes, at x=xf along the line that passes through the focus of the parabola,
∂ψ∂x|xf=0
∂2ψ∂x2|xf=0
on the parabola profile. But at the focus, the effect of ψ, and the rate of change of ψ,
∂ψ∂t≠0
We are looking at the solutions of a partial differential equation not an algebraic equation. Strictly speaking,
∂2ψ∂x2|xf=0
cannot be substituted into
∂ψ∂x∂ψ∂t=c2p√2.∂2ψ∂x2.e−iπ/4
before solving the equation. But intuitively,
∂ψ∂x∂ψ∂t=0
seems valid along x=xf and ψ varies due to a change in t, time only.