Making It Sparkle

Density of diamond $3515\,kgm^{-3}$,  $Z=6$,

$v_{boom}=3.4354*\cfrac{3515}{6}=2012.57\,ms^{-1}$

$T_{boom}=2012.57^2*\cfrac{12*10^{-3}}{3*8.3144}=1948.64\,K$  or  $1675.49^oC$

$T_{p}=2012.57^2*\cfrac{12*10^{-3}}{2*8.3144}=2922.96\,K$  or  $2649.81^oC$

Can we cook carbon in an inert environment first at $T_{boom}=1675.49^oC$ and then at $T_{p}=2649.81^oC$,  and expect diamond.  Carbon has a sublimation temperature of $3917\,K$  or  $3642\,^oC$; both $T_{boom}$ and $T_{p}$ are below this temperature.

Pressure would be needed to compact the carbon mass as the crystals form.

Maybe...