Constant Reminder

This event on 12 Aug 2018 is important,  I need a note of it.

Now, where is my post "Planck Constantly", I lost my train of thought without it...where to go from here?

Anyway,  $MgCO_3$ does not seem to be a good store of $CO_2$ because two $MgCO_3$ takes up an $O_2$.

If paired bonds is for real,

$AB=\sqrt{116.3^2+2*\left(\cfrac{116.3}{2}\right)^2}$

$AB=142.43\,pm$

Maybe a electromagnetic wave of wavelength, $\lambda=AB$

$f=\cfrac{c}{\lambda}=\cfrac{299792458}{142.43*10^{-12}}$

$f=2.1047*10^{18}\,Hz=2.1047\,EHz$

passing along the length of the $CO_2$ molecule will interrupt the electrons in the two shared paired orbits around the carbon atom and free all three radicals.

The carbon atom regains the electrons and completes/neutralize its outer shell.

Not that such a EMW is possible; but are regions of low electric density similarly spaced apart is possible on a flat substrate.  Such a substrate can act as a catalyst in decomposing $CO_2$ into its constituent elements.

What metal or metal alloy has an atomic distance of $0.142\,nm$?  Or a atomic radius of $71.22\,pm$?

None!

But, Argon $Ar$ has a atomic radius of $71\,pm$.  Carbon $C$ has a atomic radius of $70\,pm$

And so, we use a graphene sheet with a pulsating high voltage, below which we pass $CO_2$ gas, maybe carbon will start falling from the ceiling.

Maybe...but $O$ radicals released will corrode the graphene immediately.  The oxygen radical must be encouraged to form into $O_2$ immediately.

...