Now, where is my post "Planck Constantly", I lost my train of thought without it...where to go from here?
Anyway, \(MgCO_3\) does not seem to be a good store of \(CO_2\) because two \(MgCO_3\) takes up an \(O_2\).
If paired bonds is for real,
\(AB=\sqrt{116.3^2+2*\left(\cfrac{116.3}{2}\right)^2}\)
\(AB=142.43\,pm\)
Maybe a electromagnetic wave of wavelength, \(\lambda=AB\)
\(f=\cfrac{c}{\lambda}=\cfrac{299792458}{142.43*10^{-12}}\)
\(f=2.1047*10^{18}\,Hz=2.1047\,EHz\)
passing along the length of the \(CO_2\) molecule will interrupt the electrons in the two shared paired orbits around the carbon atom and free all three radicals.
The carbon atom regains the electrons and completes/neutralize its outer shell.
Not that such a EMW is possible; but are regions of low electric density similarly spaced apart is possible on a flat substrate. Such a substrate can act as a catalyst in decomposing \(CO_2\) into its constituent elements.
What metal or metal alloy has an atomic distance of \(0.142\,nm\)? Or a atomic radius of \(71.22\,pm\)?
None!
But, Argon \(Ar\) has a atomic radius of \(71\,pm\). Carbon \(C\) has a atomic radius of \(70\,pm\)
And so, we use a graphene sheet with a pulsating high voltage, below which we pass \(CO_2\) gas, maybe carbon will start falling from the ceiling.
Maybe...but \(O\) radicals released will corrode the graphene immediately. The oxygen radical must be encouraged to form into \(O_2\) immediately.
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