Monday, March 28, 2022

Measuring Crystal Field \(\chi\)

 Do this make sense?


\(V_{out}\) is the integration of voltage \(V_{in}\) within a period of \(\cfrac{1}{15.088}\,\,ms\).  To adjust for a period of one second.

\(\chi=15.088*10^{3}*V_{out}\) in units of \(Vs\) or \(Wb\)

where \(\chi\), is the measured flux in the crystal field.   Where the gain of the circuit is set to one.

\(V_{out}\) is the rms value of a time varying signal, taken with a voltmeter set to measure AC voltage.

\(V_{in}\) is not likely to be a perfect sinusoidal.

It is assumed here that a varying \(\chi\) field at the crystal induces a voltage \(V_{in}\) at a resonance frequency of  \(15.088\,kHz\).  This voltage is not used directly as a measure of the field, but instead the application of such a voltage over time (1 s) in a reciprocal circuit that generate a similar flux is used as the measure of the flux pick up by the crystal.

The key is the ability to amplify the field at a resonance of \(15.088\,kHz\) using an electrical voltage\(V_{in}\)

Right or wrong?