Doing Things In The Cold

For Ferrosilicon with $35\%$ $Si$ by weight, we adjust the density value by,

$\rho_{Si\,35}=\cfrac{28.085*0.35}{28.085*0.35+55.845*0.65}*density\,of\,Ferrosilicon$

 This is the density of $Si$ alone, in a volume of ferrosilicon, $Si\,35\%$.

$\rho_{Si\,35}=\cfrac{28.085*0.35}{28.085*0.35+55.845*0.65}*5.65=1.204\,gcm^{-3}$

$v_{boom}=3.4354*\cfrac{1.204*10^{3}}{14}=295.44\,ms^{-1}$

$T_{boom}=295.44^2*\cfrac{28.085*10^{-3}}{3*8.3144}=98.281\,K$  or $-174.87\,^oC$

$T_{p}=295.44^2*\cfrac{28.085*10^{-3}}{2*8.3144}=147.41\,K$  or $-125.74\,^oC$

It would be interesting when ferrosilicon $Si\,\,35\%$ is subjected to these temperatures.