Doing Things In The Cold

For Ferrosilicon with \(35\%\) \(Si\) by weight, we adjust the density value by,

\(\rho_{Si\,35}=\cfrac{28.085*0.35}{28.085*0.35+55.845*0.65}*density\,of\,Ferrosilicon\)

 This is the density of \(Si\) alone, in a volume of ferrosilicon, \(Si\,35\%\).

\(\rho_{Si\,35}=\cfrac{28.085*0.35}{28.085*0.35+55.845*0.65}*5.65=1.204\,gcm^{-3}\)

\(v_{boom}=3.4354*\cfrac{1.204*10^{3}}{14}=295.44\,ms^{-1}\)

\(T_{boom}=295.44^2*\cfrac{28.085*10^{-3}}{3*8.3144}=98.281\,K\)  or \(-174.87\,^oC\)

\(T_{p}=295.44^2*\cfrac{28.085*10^{-3}}{2*8.3144}=147.41\,K\)  or \(-125.74\,^oC\)

It would be interesting when ferrosilicon \(Si\,\,35\%\) is subjected to these temperatures.